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SVETLANKA909090 [29]
3 years ago
8

If you know abc=def can you state bc=ef​

Mathematics
1 answer:
tia_tia [17]3 years ago
7 0

Answer:

CPCTC

Step-by-step explanation:

If abc=def is given,

then using the cpctc rule. (corresponding parts of congruent triangles are congruent) should state this answer.

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The altitude of an equilateral triangle is 9 inches. Find the perimeter of the triangle in inches.
Fiesta28 [93]
If we  draw a perpendicular line from one of the vertices of the triangle we get  2 right angled triangles  each with  altitude 9 ins  and vertex angle = 30 degrees.   So:-

cos 30 = 9 /h     where h = one of the sides of the equilateral triangle

h =  9 / cos 30  =  10.392 inches

Therefore the perimeter of the triangle = 3 * 10.392 =  31.1769 ins

Answer is 31.18 inches to the nearest hundredth.
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Drag step's into the order to correctly solve the equation 4×=112​
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Read 2 more answers
A triangle is graphed in the coordinate plane. The vertices of the triangle have coordinates (–3, 1), (1, 1), and (1, –2). What
vladimir2022 [97]

Answer:

The perimeter of the triangle is 12\ units

Step-by-step explanation:

Let

A(-3,1),B(1,1),C(1,-2)

we know that

The perimeter of triangle is equal to

P=AB+BC+AC

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the distance AB

A(-3,1),B(1,1)

substitute in the formula

AB=\sqrt{(1-1)^{2}+(1+3)^{2}}

AB=\sqrt{(0)^{2}+(4)^{2}}

AB=4\ units

step 2

Find the distance BC

B(1,1),C(1,-2)

substitute in the formula

BC=\sqrt{(-2-1)^{2}+(1-1)^{2}}

BC=\sqrt{(-3)^{2}+(0)^{2}}

BC=3\ units

step 3

Find the distance AC

A(-3,1),C(1,-2)

substitute in the formula

AC=\sqrt{(-2-1)^{2}+(1+3)^{2}}

AC=\sqrt{(-3)^{2}+(4)^{2}}

AC=5\ units

step 4

Find the perimeter

P=AB+BC+AC

substitute the values

P=4+3+5=12\ units

6 0
3 years ago
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