Answer:
Delivered small RNAs can inhibit protein A production through the RNA interference (RNAi) mechanism, and thus impairs angiogenesis
Explanation:
The pregnancy-associated plasma protein-A is a protease enzyme involved in the formation of new blood vessels by increasing insulin-like growth factor I (IGF-I) bioavailability. Moreover, small RNAs (<200 nucleotides in length, generally 18 to 30 nucleotides) are non-coding RNA molecules that function in RNA silencing through the RNA interference (RNAi) pathway. Small RNAs are widely used in molecular biology laboratories because they can be delivered into specific cells in order to silence target mRNAs such as, in this case, the mRNA encoding protein A, by complementary base pairing and thereby inducing translational repression. In consequence, mRNAs complementary to delivered small RNAs are silenced through RNAi pathways, i.e., by cleavage of the target mRNA and/or mRNA destabilization.
Answer:
i think its A. i dunno if it is btw have a nice day
Answer:
The double membrane of the mitochondria is highly folded,and therefore wider when unfolded than that of the nucleus.This is an adaptive feature to increase the surface area for reactions (electrochemical gradient) by accommodating protons pumped into it by the proton motive force(PMF) from the matrix to set up the electrochemical gradients needed to generate the energy needed by ATPase synthase enzymes for ATPs synthesis.
Required number of protons needed to be accommodated by the double membrane to generate enough energy for ATPase synthesis,therefore larger surface area is needed.
Explanation:
<span>F- allele for freckles
f- </span><span>allele without freckles
1) The man is heterozygote and has freckles, its indicating that the allele for freckles is dominant.
A cross between him and a woman who is also </span><span>heterozygote: Ff x Ff
it would result in the following probabilities:
- 1/4 - homozygote with freckles: FF
- 2/4 - </span><span>heterozygote with freckles: Ff
- 1/4- </span><span>homozygote without freckles:ff
Their son would have a probability of 75% of being born with freckles.
2) The cross resulted in this probabilities:
</span><span><span>- 1/4 - homozygote with freckles: FF
- 2/4 - </span><span>heterozygote with freckles: Ff
- 1/4- </span><span>homozygote without freckles:ff
So, the chance of being born heterozygote for this gene is 2/4, which is the same as half (50%).
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