Starting from a single individual, what is the size of a population of bacteria that reproduce by binary fission every 20 minute s at the end of a 2-hour time period? (Assume unlimited resources and no mortality.)
1 answer:
Answer:
C) 128
Explanation:
In binary fission each bacterial cell will divide into two parts.
1. Since the bacteria divides divides after every 20 min , We have to find the number of division in two hours two hour(2x60=120 min) which will be;
120÷20=6
It will undergo 6 divisions.
2. To calculate the number of bacteria at the end of 2 hours
Bacteria in the beginning x 2∧ Number of division
1× 2∧6= 128 Bacteria
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