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hram777 [196]
3 years ago
7

Starting from a single individual, what is the size of a population of bacteria that reproduce by binary fission every 20 minute

s at the end of a 2-hour time period? (Assume unlimited resources and no mortality.)
A) 6
B) 18
C) 128
D) 512
E) 1,024
Biology
1 answer:
masya89 [10]3 years ago
6 0

Answer:

 C) 128

Explanation:

In binary fission each bacterial cell will divide into two parts.

1. Since the bacteria divides divides after every 20 min , We have to find the number of division in two hours two hour(2x60=120 min) which will be;

120÷20=6

It will undergo 6 divisions.

2. To calculate the number of bacteria at the end of 2 hours

Bacteria in the beginning x 2∧ Number of division

1× 2∧6= 128 Bacteria  

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b. multicellular fungus

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Answer:

a. Genotype in F1 - TtBb

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TtBb   x   TtBb

Progeny

1 TTBB   -   tough pods, bush-type

2 TTBb     -  tough pods, bush-type

2 TtBB    -   tough pods, bush-type

4 TtBb     -   tough pods, bush-type

1 TTbb     -    tough pods, climbing-type

2 Ttbb     -    tough pods, climbing-type

1 ttBB       -    tender pods, bush-type

2 ttBb     -      tender pods, bush-type

1 ttbb      -      tender pods, climbing-type

<em>Proportion of F2 that are heterozygous for bush-type growth form = 10/16 = 5/8</em>

<em>Proportion of the F2 with tender pods = 4/16 = 1/4</em>

<em>Proportion of F2 that are heterozygous for growth form and have tender pods = 2/16 = 1/8</em>

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