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julia-pushkina [17]

3 years ago

6

Jana earns $25 per week for mowing the lawn and deposits the money into her savings account. The amount of money in Jana’s accou

nt can be represented by the equation y=25x + 125, where x is the number of weeks she has been mowing the lawn. What does the y-intercept of the graph represent in this situation?

1 answer:

photoshop1234 [79]3 years ago

7 0

Slope-intercept form: y = mx + b [m is the slope, b is the y-intercept or the y value when x = 0 ---> (0, y) or the point where the line crosses through the y-axis]

y = 25x + 125

"y" would represent the total amount of $ she has saved.

The y-intercept would be 125 or (0, 125), this means that she already/initially had $125 in her savings account, before she started depositing $25 per week

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TiliK225 [7]

7.48331477355

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6 0

3 years ago

Nilai x yang memenuhi persamaan linier dari 2x-7/2=3-6-5x/6 adalah

emmainna [20.7K]

2x-7/2 = 3-6-5x/6
⇒ 2x+ 5x/6= -3+ 7/2
⇒ 2 5/6x= 1/2
⇒ x= (1/2)/ (2 5/6)
⇒ x= 3/17

The final answer is x= 3/17~

5 0

4 years ago

stepan [7]

Answer:

$Area = 129.5m^2$

$Perimeter = 48m$

Step-by-step explanation:

Given

See attachment

Required

Determine the area and the perimeter of the garden

Calculating Area

First, we calculate the $area\ of\ the\ rectangle$

$A_1 = L * B$

Where:

$L = 20-(3.5 +3.5)$

$B = 7$

So:

$A_1 = (20 - (3.5 + 3.5)) * 7$

$A_1 = (20 - 7) * 7$

$A_1 = 13 * 7$

$A_1 = 91$

Next, we calculate the area of the two semi-circles.

Two semi-circles = One Circle

So:

$A_2 = \pi r^2$

Where

$r = \frac{7}{2}$

$A_2 = \frac{22}{7} * (\frac{7}{2})^2$

$A_2 = \frac{22}{7} * \frac{49}{4}$

$A_2 = \frac{22}{1} * \frac{7}{4}$

$A_2 = \frac{22*7}{4}$

$A_2 = \frac{154}{4}$

$A_2 = 38.5$

Area of the garden is

$Area = A_1 + A_2$

$Area = 91 + 38.5$

$Area = 129.5m^2$

Calculating Perimeter

First, we calculate the perimeter of the rectangle

But in this case, we only consider the length because the widths have been covered by the semicircles

$P_1 = 2 * L$

Where:

$L = 20-(3.5 +3.5)$

So:

$P_1 =2 * (20-(3.5 +3.5))$

$P_1 =2 * (20-7)$

$P_1 =2 * 13$

$P_1 =26$

Next, we calculate the perimeter of the two semi-circles.

Two semi-circles = One Circle

So:

$P_2 = 2\pi r$

Where

$r = \frac{7}{2}$

$P_2 = 2 * \frac{22}{7} * \frac{7}{2}$

$P_2 = \frac{2 * 22 * 7}{7 * 2}$

$P_2 = \frac{308}{14}$

$P_2 = 22$

Perimeter of the garden is

$Perimeter = P_1 + P_2$

$Perimeter = 26 + 22$

$Perimeter = 48m$

8 0

3 years ago

2. The dimensions of a triangular pyramid are shown on the figure below. The height of the pyramid is

k0ka [10]

Answer:

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7 0

4 years ago

20 points and a branliest if correct, ASAP please

xenn [34]

You are going to use the cos trig function as you have the adjacent side and the hypotenuse.
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22.62

4 0

3 years ago