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mamaluj [8]
3 years ago
8

13??? pls also explain how u do it

Chemistry
1 answer:
Lady_Fox [76]3 years ago
7 0

Answer:

d. it has a high boiling point

Explanation:

all ionic compounds with ionic bonds have high boiling points

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How does adding oxygen (O2) to this reaction change the equilibrium? 2SO2(g) + O2(g) ⇌ 2SO3(g) A. The equilibrium shifts right t
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The equilibrium law or the Le Chatelier's principle states that when a system encounters a disturbance like a temperature, concentration, or pressure modifications, it will react to restore a new state of equilibrium.  

In the given case, adding reactant, that is, oxygen will shift the reaction in the direction of the product, on the basis of Le Chatelier's principle. Thus, the equilibrium will move toward the product side. So, the correct answer will be option A, that is, the equilibrium shifts right to produce more SO₃ molecules.  


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Use the drop Dow menus to select the names of the labeled structures
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3 years ago
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A quantity of 0.27 mole of neon is confined in a container at 2.50 atm and 298 Kand then allowed to expand adiabatically under t
valentinak56 [21]

Answer:

a) Hence, T = 207 K.

b) Hence, T2 = 226 K.

Explanation:

Now the given,

n = 0.27 moles ; P = 2.5 atm ; T = 298 K

a) γ = 5/3 since Ne is a monoatomic gas.

(1 - \gamma )/\gamma  = -2/5\\T1 P1^{(1-\gamma)/\gamma}=T2 P2^{(1-\gamma)/\gamma}\\T2 = T1(P1/P2)^{(1 - \gamma)/\gamma}\\T2 = 298 (2.5/1)^{-2/5}= 207 K\\

Hence, T = 207 K

b) We know that,U = W = n Cv (T2 - T1) = -P (V2 - V1)

n(3/2)R(T2 - T1) = -P( n R T2/P2 - n R T1/P1)\\3/2(T2 - T1) = -P (T2/P2 - T1/P1)

But P = P2

3/2(T2 - T1) = -P2(T2/P2 - T1/P1)\\3/2(T2 - T1) = -T2 + P2T1/P1

This gives us:

T2 = 2/5(P2/P1 + 3/2)T1\\T2 = 2/5 x (1 /2.5 + 3/2)/(298)\\T2 = 19/25 x 298 = 226 K

Hence, T2 = 226 K

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2 years ago
What are the correct names of the numbered stages (legs) of the phase diagram
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The answer is B because the phase hangs is increasing heat
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