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VLD [36.1K]
3 years ago
15

Using seismographs from different locations allows scientists to determine the __________ of an earthquake. A) epicenter, B) App

roximate cost, C) Damage, D) Cause.
Chemistry
2 answers:
SVETLANKA909090 [29]3 years ago
6 0
I did the test and its A for sure.
fredd [130]3 years ago
5 0

The answer is: A) epicenter.

Seismometer is an instrument that measures ground motions and the point where an earthquake originates (epicenter).

It is build of a mass attached to a fixed base; during an earthquake, the base moves and the mass does not.

Seismograph records the times when the first (P waves) and second (S waves) seismic waves arrive. Then, scientists determine how fast the waves are traveling and at the end calculate the distance from the epicenter to each seismograph.

You might be interested in
B. What useful functions do oxidation numbers
disa [49]

Explanation:

b. What useful functions do oxidation numbers  serve?

It is used to show oxidation and reduction (loss and gain of electrons)

b. How many molecules are in 1 mole of  molecules?

1 mole = 6.022 * 10^23 molecules

c. What is the name given to the number of  molecules in 1 mole?

Avogadro's Number of molecules

21. a. What is the molar mass of an element?

This is the mass of an element divided by the number of moles.

Molar mass = Mass / Number of moles

b. Write the molar mass rounded to two  decimal places of carbon, neon, iron and  uranium.

amu = Atomic Mass Unit

Carbon = 12.01 amu

Neon = 20.18 amu

Iron = 55.85 amu

Uranium = 238.03 amu

7 0
3 years ago
1.How many mL of 0.401 M HI are needed to dissolve 5.97 g of BaCO3?
garri49 [273]

Answer:

The answer to your question is:

1.- volume = 0.151 l or 151 ml

2.- 0.241 l  or 241 ml of NaOH

Explanation:

1.-

Data

V = ? HI = 0.401 M

BaCO3 = 5.97 g

                     2HI(aq)    +    BaCO3(s)   ⇒   BaI2(aq) + H2O(l) + CO2(g)

MW BaCO3 = 137 + 12 + 48 = 197 g

                     197 g of BaCO3 ----------------- 1 mol

                     5.97 g                -----------------   x

                     x = (5.97 x 1) /197

                    x = 0.03 mol of BaCO3

                    2 moles of HI ----------------  1 mol of BaCO3

                    x                     ----------------  0.03 mol of BaCO3

                    x = (0.03 x 2) / 1

                   x = 0.060 mol of HI

Molarity = moles / volume

volume = moles / molarity

volume = 0.060 / 0.401

volume = 0.151 l or 151 ml

2.-

V = ?    NaoH 0.757 M

Co⁺² Volume = 167 ml   0.548 M

             CoSO4(aq) + 2NaOH(aq)   ⇒   Co(OH)2(s) + Na2SO4(aq)

Moles of Co = Molarity x  volume

Moles of Co = 0.548 x 0.167

Moles of Co = 0.092

                                 1 mol of CoSO4 -------------- 2 moles of NaOH

                                0.092 moles      ---------------   x

                                x = (0.092 x 2) /1

                               x = 0.183 moles of NaOH

Volume of NaOH = moles / molarity

                             = 0.183 / 0.757

                            = 0.241 l  or 241 ml of NaOH

6 0
3 years ago
Using the periodic tables, identify the heaviest member of each of the following groups:
Lady_Fox [76]

Answer:

(a) Alkali metals: Francium (Fr)

(b) Chalcogens: Polonium (Po)

(c) Noble gases: Radon (Rn)

(d) Alkaline earth metals: Radium (Ra)

Explanation:

In the periodic table, the atomic mass increases down the group. Therefore, the last element of a group is the heaviest element of the group.

(a) alkali metals: The chemical elements that are present in group 1 of the periodic table, except hydrogen.

<u>The heaviest member of this group is francium (Fr)</u>

(b) chalcogens: The chemical elements that are present in group 16 of the periodic table

<u>The heaviest member of this group is polonium (Po)</u>

(c) noble gases:  The chemical elements that are present in group 18 of the periodic table

<u>The heaviest member of this group is radon (Rn)</u>

(d) alkaline earth metals: The chemical elements that are present in group 2 of the periodic table.

<u>The heaviest member of this group is radium (Ra)</u>

7 0
3 years ago
Carry out the following operations as if they were calculations of experimental results and express each answer in standard nota
Shalnov [3]

Answer:

1. 10.6\; \rm m (one decimal place.)

2.0.79\; \rm g (two decimal places.)

3. 16.5\;\rm cm^2 (three significant figures.)

Explanation:

<h3>1.</h3>

The first and second expressions are additions and subtractions. When adding two numbers, the accuracy of the result is given by the number of decimal places in it. The result should have as many decimal places as the input with the least number of decimal places.

For example, in the first expression:

  • 5.6792\;\rm m has four decimal places.
  • 0.6\; \rm m has only one decimal place.
  • 4.33\; \rm m has two decimal places.

Therefore, the result should be rounded to one decimal place. Note that these units are compatible for addition, since they are all the same. The result should have the same unit (that is: \rm m.)

Therefore:

\rm 5.6792\; m + 0.6\; m + 4.33\; m \approx 10.6\; \rm m. (Rounded to one decimal place.)

<h3>2.</h3>

Similarly:

  • \rm 3.70\; \rm g has two decimal places.
  • 2.9133\; \rm g has four decimal places.

Therefore, the result should be rounded to two decimal places. Its unit should be \rm g (same as the unit of the two inputs.)

\rm 3.70\; g - 2.9133\; g \approx 0.79\; \rm g. (Rounded to two decimal places.)

<h3>3.</h3>

When multiplying two numbers, the accuracy of the result should be based on the number of significant figures in it. The result should have as many significant figures as the input with the least number of significant figures. In this expression:

  • 4.51\; \rm cm has three significant figures.
  • 3.6666\; \rm cm has five significant figures.

Therefore, the result should have only three significant figures.

The unit of the result is supposed to be the product of the units of the input. In this expression, that unit will be \rm cm \cdot cm, which is occasionally written as \rm cm^2.

\rm 4.51 \; cm \times 3.6666 \; cm \approx 16.5\; \rm cm^2. (Rounded to three significant figures.)

7 0
3 years ago
Cuales son los símbolos para representar que una reacción se produce en presencia de;
ycow [4]

Answer:

b

Explanation:

3 0
2 years ago
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