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svet-max [94.6K]
3 years ago
15

What are the two processes underlying this image that turn peat into coal

Chemistry
2 answers:
Travka [436]3 years ago
8 0

Answer:

Peatification and coalification

Explanation:

https://energyeducation.ca/encyclopedia/Coal_formation

blsea [12.9K]3 years ago
7 0

Answer: Option (D)

Explanation: In order to form coal, two processes might be undergone and they are as follows-

  1. Peatification- It is the process by which the remains of trees and plants undergoes partial decomposition in a swampy type of environment, conserving organic matter. It is the first stage of coal formation.
  2. Coalification- It is the process of complete transformation of the dead remains of plants and trees into coal.

Thus the correct answer is option (D).

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Energy transfer by convection is usually restricted to what type of substance? A. Solids only
Lunna [17]

My thought would be B) gases.

I could be wrong but that's what i'd say


4 0
3 years ago
In a 100 g sample of iron(III) oxide, how many grams of iron are present?
e-lub [12.9K]
The formula of Iron(III) oxide is Fe2O3
In order to calculate the mass of iron in a given sample of iron(III) oxide, we must first know the mass percentage of iron in iron(III) oxide. This is calculated by:
[mass of iron in one mole of iron(III) oxide/ mass of one mole of iron(III) oxide] * 100 
= [(moles of iron * Mr of iron) / (moles of Iron * Mr of Iron + moles of Oxygen * Mr of Oxygen)] * 100
= [(2 * 56) / (2 * 56 + 3 * 16)] * 100
= (112 / 160) * 100
= 70%
Thus, in a 100g sample, the weight of iron will be:
100 * 70%
= 70 grams
8 0
3 years ago
According to the law of conservation of mass,why is it considered a mistake to add calcium to the product side if it is not in t
ser-zykov [4K]
<span>According to the law of conservation of mass, the masses of the products and reactants must be the same. Adding calcium to the product side is considered a mistake if it is not in the reactant side of a particular chemical equation because it is impossible to produce calcium from thin air (unless this is a nuclear reaction).</span>
5 0
3 years ago
Which structures are haploid? select all that apply. which structures are haploid? select all that apply. gametophyte spores zyg
spayn [35]
<span>While looking at the life cycle of fern the structures that categorized under haploid are Egg, Spores, and Gametophyte. Spores are haploids that are in turn turned into haploid gametophytes through mitosis. The haploid gametophytes produce gametes and eggs also through mitosis which are haploid.</span>
6 0
3 years ago
A sample of a gas contains 0.305 g of carbon, 0.407 g of oxygen and 1.805 g of chlorine. A different sample of the same gas havi
Umnica [9.8K]

Answer:

Molecular formula = empirical formula  = COCl2

Explanation:

Step 1: Data given

MAss of carbon = 0.305 grams

MAss of oxygen = 0.407 grams

Mass of chlorine = 1.805 grams

A different sample of the same gas having a mass of 8.84 g occupies 2 L at STP

Atomic mass of C = 12.01 g/mol

Molar mass of O2 = 16.0 g/mol

Molar mass of Cl2 = 35.45 g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles C = 0.305 grams / 12.01 g/mol

Moles C = 0.0254 moles

Moles O = 0.407 grams / 16.0 g/mol

Moles O = 0.0254 moles

Moles Cl = 1.805 grams / 35.45 g/mol

Moles Cl = 0.0509 moles

Step 3: Calculate the mol ratio

We divide by the smallest amount of moles

C: 0.0254 moles / 0.0254 moles = 1

O: 0.0254 moles / 0.0254 moles = 1

Cl: 0.0509 / 0.0254 = 2

The empirical formula is COCl2

Step 4: Calculate moles

At STP we have 22.4 L for 1 mol

For 2 L we have 1 / 11.2 = 0.0893 moles

Step 5: Calculate the molar mass

Molar mass = mass / moles

Molar mass = 8.84 grams / 0.0893 moles

Molar mass = 98.99 g/mol

Step 6: Calculate the molar mass of the empirical formula

COCl2 = 12.01 + 16.0 + 70.9 ≠ 98.91 g/mol

Step 7: Calculate the molecular formula

Molecular formula = empirical formula  = COCl2

4 0
2 years ago
Read 2 more answers
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