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svet-max [94.6K]
3 years ago
15

What are the two processes underlying this image that turn peat into coal

Chemistry
2 answers:
Travka [436]3 years ago
8 0

Answer:

Peatification and coalification

Explanation:

https://energyeducation.ca/encyclopedia/Coal_formation

blsea [12.9K]3 years ago
7 0

Answer: Option (D)

Explanation: In order to form coal, two processes might be undergone and they are as follows-

  1. Peatification- It is the process by which the remains of trees and plants undergoes partial decomposition in a swampy type of environment, conserving organic matter. It is the first stage of coal formation.
  2. Coalification- It is the process of complete transformation of the dead remains of plants and trees into coal.

Thus the correct answer is option (D).

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Kate’s blood volume is 3.8L. Before treatment,if her blood glucose was 170 mg/dL, how many grams of glucose were in her blood?
LiRa [457]

Answer:

6.460 gm  is the correct answer .

Explanation:

Given

Kate’s blood volume=3.8L

blood glucose=170\  mg/dL

As we know that

1\ dL= 10^{-1}\ litre

The 10^{-1}   includes the blood glucose of the 170\  mg/dL,

So 3.8L. of the Kate’s blood volume  can be determined by

=\ \frac{170 * 3.8 }{10^{-1} }

=170 * 38 \ mg

=6460\ mg

To convert into the gm we have divided by the 1000

6.460 \ gm

Therefore the glucose in her blood=

6.460 \ gm

3 0
3 years ago
Read 2 more answers
Write nuclear symbols for each of the isotopes Carbon-14 Cobalt-60 Gold-197 Uranium-235
Marina CMI [18]

Answer and explanation:

The nuclides with the same atomic number, but different mass numbers are isotopes.

So, in this case, each species will have the same atomic number and a different mass number, that will be the same that it is written in the name of the element:

\begin{gathered} -\text{ Carbon-14:}C_6^{14} \\  \\ -\text{ Cobalt-60: }Co_{27}^{60} \\  \\ -\text{ Gold-197:  }Au_{79}^{197} \\  \\ -\text{ Uranium-235: }U_{92}^{235} \end{gathered}

5 0
1 year ago
Do anyone know how to do question B
Over [174]

Answer:

a) IUPAC Names:

                   1) (<em>trans</em>)-but-2-ene

                   2) (<em>cis</em>)-but-2-ene

                   3) but-1-ene

b) Balance Equation:

                       C₄H₁₀O + H₃PO₄   →   C₄H₈ + H₂O + H₃PO₄

As H₃PO₄ is catalyst and remains unchanged so we can also write as,

                                    C₄H₁₀O   →   C₄H₈ + H₂O

c) Rule:

           When more than one alkene products are possible then the one thermodynamically stable is favored. Thermodynamically more substituted alkenes are stable. Furthermore, trans alkenes are more stable than cis alkenes. Hence, in our case the major product is trans alkene followed by cis. The minor alkene is the 1-butene as it is less substituted.

d) C is not Geometrical Isomer:

        For any alkene to demonstrate geometrical isomerism it is important that there must be two different geminal substituents attached to both carbon atoms. In 1-butene one carbon has same geminal substituents (i.e H atoms). Hence, it can not give geometrical isomers.

7 0
3 years ago
Find the cell potential for a system whose ∆G = +55 kJ and 3 moles of electrons are exchanged.
rosijanka [135]

Answer:- cell potential = -0.19 volts

Solution:- The equation that shows the connection between \Delta G and cell potential, E is written  as:

\Delta G=-nFE

in this equation, n stands for moles of electrons, E stands for cell potential and F stands for faraday constant and it's value is \frac{96485C}{mol} .

It asks to calculate the value of E, so let's rearrange the equation:

E=-\frac{\Delta G}{nF}

Let's plug in the values in it:

E=-\frac{55kJ}{3mol*96485C.mol^-}

E=-\frac{0.00019kJ}{C}

since, \frac{1kJ}{C}=1000V

Where C stands for coulombs and V stands for volts.

So, E=-\frac{0.00019kJ}{C}(\frac{1000V}{\frac{1kJ}{C}})

E = -0.19 V

So, the cell potential is -0.19 volts.


4 0
3 years ago
The only way to determine the products of a reaction is to carry out the reaction. All chemical reactions can be classified as o
myrzilka [38]

Answer:

All the statements are correct but "all chemical reactions can be classified as one of the five general types".

Explanation:

Hello,

In this case, I assume you are looking for the wrong statement as long as the following ones are correct and matches with the foundations of chemical reactions:

- The only way to determine the products of a reaction is to carry out the reaction. This is clear, because after the chemical reaction is done, one identifies the products.

- Complete combustion has occurred when all the carbon in the product is in the form of carbon dioxide. This is clear due to a 100% conversion.

- A single reactant is the identifying characteristic of a decomposition reaction. All decomposition reactions have only one reactant which breaks into less complex species.

So the wrong statement is:

- All chemical reactions can be classified as one of five general types. This is wrong because there are four widely known chemical reactions: synthesis, decomposition, simple displacement and double displacement.

Best regards.

8 0
4 years ago
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