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zlopas [31]
2 years ago
10

Define the following terms. a. Capillary action b. Chromatogram

Chemistry
1 answer:
jonny [76]2 years ago
6 0

Answer:

<em>1</em><em>.</em><em>Capillary action is important for moving water (and all of the things that are dissolved in it) around. </em>

<em>2</em><em>.</em><em>the pattern formed on an adsorbent medium by the layers of components separated by chromatography. </em>

Explanation:

hope this help you

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What is the gram-formula mass of Fe(NO3)3?
dusya [7]
M Fe = 55,85g ≈ 56g
m O = 16g
m N = 14g
m Fe(NO3)3 = 56g + 3*14g + 3*3*16g = 242g/mol

answer: (4)
8 0
2 years ago
Read 2 more answers
Which statements describe an element? Check all that apply.
Molodets [167]

Answer:

<em>Hello, Your answer will be B,C,E, And F.</em>

Explanation:

An element is a substance whose atoms have same number of protons which means all atoms in an element have same atomic number. Elements are simplest substances which cannot be broken down by physical changes or chemical reactions. Elements are classified by their names and symbols. Hope That Helps!

8 0
3 years ago
What happens when gases change to plasma?
IgorLugansk [536]

Answer:. In the case of neon, it is electrical energy that pulls the electrons off.

explanation-Plasma can be made from a gas if a lot of energy is pushed into the gas. In the case of neon, it is electrical energy that pulls the electrons off. When it is time to become a gas again, just flip the neon light switch off. Without the electricity to energize the atoms, the neon plasma returns to its gaseous state.

8 0
3 years ago
0.28gram of NH3 on decomposition gave 0.25gram of nitrogen and hydrogen. Find the volume of hydrogen evolved at Ntp. (2gram hydr
hodyreva [135]

The volume of H₂ evolved at NTP=0.336 L

<h3>Further explanation</h3>

Reaction

Decomposition of NH₃

2NH₃ ⇒ N₂ + 3H₂

conservation mass : mass reactants=mass product

0.28 NH₃= 0.25 N₂ + 0.03 H₂

2 g H₂ = 22.4 L

so for 0.03 g :

\tt \dfrac{0.03}{2}\times 22.4=0.336

7 0
3 years ago
A 6.40 g sample of a compound is burned to produce 8.37 g CO_2, 2.75 g H_2O, 1.06 g N_2, and 1.23 g SO_2. What is the empirical
LuckyWell [14K]

The empirical formula :

C₁₀H₁₆N₄SO₇

<h3>Further explanation</h3>

Given

6.4 g sample

Required

The empirical formula

Solution

mass C :

= 12/44 x 8.37 g

= 2.28

mass H :

= 2/18 x 2.75 g

= 0.305

mass N = 1.06

mass S :

= 32/64 x 1.23

= 0.615

mass O = 6.4 - (2.28+0.305+1.06+0.615) = 2.14 g

Mol ratio :

= C : H : N : S : O

= 2.28/12 : 0.305/1 : 1.06/14 : 0.615/32 : 2.14/16

= 0.19 : 0.305 : 0.076 : 0.019 : 0.133 divided by 0.019

= 10 : 16 : 4 : 1 : 7

The empirical formula :

C₁₀H₁₆N₄SO₇

3 0
3 years ago
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