Please answer the question from the attachment.

Mathematics

2 answers:

Lelechka [254]3 years ago

6 0

Y = 4x .....(a)

3x - y = 1. ......(b)

Substitute y = 4x in (a) into (b)

3x - y = 1......(b)

3x - 4x = 1

-x = 1

x = -1

Recall, y = 4x ........(a)

y = 4*(-1)

y = -4.

Therefore, x = -1, and y = -4.

anastassius [24]3 years ago

3 0

If y = 4x then you'd input that information into your equation making: 3x-4x = 1
The correct solution is: 3(-1)-4(-1) = 1

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Very confused with this

OlgaM077 [116]

Answer:

∠ D = 28°

Step-by-step explanation:

The external angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ EBC is an exterior angle of Δ ABE, thus

∠ EBC = 90° + 34° = 124°

BD bisects ∠ EBC, so

∠ EBD = 124° ÷ 2 = 62° , then

∠ D = 180° - (90 + 62)° = 180° - 152° = 28° ( angle sum of triangle )

4 0

2 years ago

-4rover4+5rover3 please help me

Alchen [17]

$Solution, \frac{-4r}{4}+\frac{5r}{3}=\frac{2r}{3}$

$Steps:$

$\frac{-4r}{4}+\frac{5r}{3}$

$\frac{-4r}{4},\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b},\\-\frac{4r}{4},\\\mathrm{Divide\:the\:numbers:}\:\frac{4}{4}=1,\\-r,\\-r+\frac{5r}{3}$

$\mathrm{Convert\:element\:to\:fraction}:\quad \:r=\frac{r3}{3},\\\frac{5r}{3}-\frac{r\cdot \:3}{3}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c},\\\frac{5r-r\cdot \:3}{3}$