1 answer:
<span>∇ · (|r| r)
=</span>|r| <span>∇ · ( r) + r </span><span>∇ · |r|
</span>
|r| =√x²+y²+z²
<span>∇ · ( r) =dr/dx +dr/dy+dr/dz= i+j+k
so
</span>∇ · (|r| r)
=<span>√x²+y²+z² (</span><span>i+j+k) + </span><span>(x i + y j + z k ) </span>∇ · |r|
∇ · |r|= 2(x+y+z)/<span>√x²+y²+z²
finally
</span>
∇ · (|r| r)
=<span> |r|</span><span> (i+j+k) + 2(xi+yj+zk)/</span><span> |r|=</span><span>|r| (i+j+k) + 2r/</span><span>|r|</span>
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