Question

Ammonia (nh3(g), hf = –46.19 kj/mol) reacts with hydrogen chloride (hcl(g), hf = –92.30 kj/mol) to form ammonium chloride (nh4cl(s), hf = –314.4 kj/mol) according to this equation: nh3(g) + hcl(g) nh4cl(s) what is hrxn for this reaction?

Answer 1

Answer:-175.9

Explanation:

trust

Answer 2

Answer: The $\Delta H_{rxn}$ for the given chemical reaction is -175.51 kJ/mol

Explanation: Enthalpy change of the reaction is defined as the amount of heat released or absorbed in a given chemical reaction.

Mathematically,

$\Delta H_{rxn}=\Delta H_f_{(products)}-\Delta H_f_{(reactants)}$

We are given a chemical reaction. The reaction follows:

$NH_3(g)+HCl(g)\rightarrow NH_4Cl(s)$

$H_f_{(NH_3)}=-46.19kJ/mol$

$H_f_{(HCl)}=-92.30kJ/mol$

$H_f_{(NH_4Cl)}=-314.4kJ/mol$

Enthalpy change for the reaction of he given chemical reaction is given by:

$\Delta H_{rxn}=H_f_{(NH_4Cl)}-(H_f_{(NH_3)}+H_f_{(HCl)})$

Putting the values in above equation, we get

$\Delta H_{rxn}=-314.4-(-92.30-46.19)kJ/mol$

$\Delta H_{rxn}=-175.51kJ/mol$