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AveGali [126]
3 years ago
12

explain the following observation. When 3-methylbutan-2-ol is treated with HBr, a single alkyl bromide is isolated, resulting fr

om 1,2, shift. When 2-methylpropan-1-ol is treated with HBr no rearrangement occurs to form alkyl bromide

Chemistry
1 answer:
babunello [35]3 years ago
5 0

Answer:

1. For the first reaction, there is Carbonation and rearrangement

2. For the second reaction, No Carbonation, No rearrangement.

Explanation:

See attached screenshot below

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