explain the following observation. When 3-methylbutan-2-ol is treated with HBr, a single alkyl bromide is isolated, resulting fr
om 1,2, shift. When 2-methylpropan-1-ol is treated with HBr no rearrangement occurs to form alkyl bromide
1 answer:
Answer:
1. For the first reaction, there is Carbonation and rearrangement
2. For the second reaction, No Carbonation, No rearrangement.
Explanation:
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