Answer:60 %
Step-by-step explanation:
<h3>if we set up an proportion,

=

the answer is 60. </h3><h3>100x12=1200</h3><h3>1200 divded by 20 =60</h3>
Answer:
10m15n10
Step-by-step explanation:
5x2m=10m
5x3n=15n
5x2=10
so you get 10m15n10
you can't simplify it anymore because none of them have the same variables
Answer:
Step-by-step explanation:
Divide: 3/13 = 3 ÷ 13
3/13 = 0.230769230769...
B) is your answer
~
Given:
The given quadratic polynomial is :

To find:
The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.
Solution:
We have,

Equate the polynomial with 0 to find the zeroes.

Splitting the middle term, we get




The zeroes of the given polynomial are -3 and 4.
The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.
A quadratic polynomial is defined as:




Therefore, the required polynomial is
.
Answer:
y= 169 − 
Step-by-step explanation: