Answer/Step-by-step explanation:
1. B = 180 - (90 + 58) (sum of triangles)
B = 32°
Let's find a and b using trigonometric ratios:
Reference angle = 58°
Opposite = a = ?
Hypotenuse = c = 27
Adjacent = b = ?
✔️To find a, apply SOH:
Sin 58 = Opp/Hyp
Sin 58 = a/27
a = 27*Sin 58
a = 22.8972986 ≈ 22.9 (nearest tenth)
✔️To find b, apply CAH:
Cos 58 = Adj/Hyp
Cos 58 = b/27
b = 27*Cos58
b = 14.3 (nearest tenth)
2. B = 180 - (90 + 63) (sum of triangles)
B = 27°
Let's find a and b using trigonometric ratios:
Reference angle = 63°
Opposite = a = 11
Hypotenuse = c = ?
Adjacent = b = ?
✔️To find b, apply TOA:
Tan 63 = Opp/Adj
Tan 63 = 11/b
b = 11/Tan 63
b = 5.6 (nearest tenth)
✔️To find c, apply SOH:
Sin 63 = Opp/Hyp
Sin 63 = 11/c
c = 11/Sin 63
c = 12.3 (nearest tenth)
0.330000000001, 0.330000000002, 0.339999999999
First of all we need to find a representation of C, so this is shown in the figure below.
So the integral we need to compute is this:
So, as shown in the figure, C = C1 + C2, so:
Computing first integral:Applying derivative:
Substituting this value into
Computing second integral:Applying derivative:
Substituting this differential into
We need to know the limits of our integral, so given that the variable we are using in this integral is x, then the limits are the x coordinates of the extreme points of the straight line C2, so:
Finally: