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Brilliant_brown [7]
2 years ago
9

The vertex form of the equation of a parabola is y=3(x-40)^2-22. What is the standard form of the equation?

Mathematics
1 answer:
Leya [2.2K]2 years ago
3 0
<span>y=3(x-40)^2-22
y = 3(x^2 - 80x + 1600) - 22
y = 3x^2 - 240x + 4800 - 22
y = 3x^2 - 240x + 4778

answer
</span><span> standard form of the equation
</span>y = 3x^2 - 240x + 4778
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Answer:

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Step-by-step explanation:

Slope intercept form of equation is of form

y = mx+c

where m is the slope of line and c is the y intercept of the line.

Y intercept is point on y axis where the line intersects the y axis.

_____________________________

Given equation

y = -2x +4

comparing it with y = mx+ c

m = -2 , c = 4

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when two lines are parallel, their slopes are equal.

Let the equation of new line in slope intercept form be y = mx + c

Thus slope of of new required line is -2

Thus m for new line is -2.

now, equation of required line : y = -2x+c

Given that this line passes through (-4, -2). This point shall should satisfy equation  y = -2x+c.

Substituting the value of (-4, -2) we have

-2 = -2(-4)+c

=> -2 = 8 +c

=> -2 -8 = c

=> c = -10.

Thus , equation of required line is  y = -2x - 10.

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Answer:

3.9

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