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Anarel [89]
2 years ago
6

Which ratio represents the tangent of z

Mathematics
1 answer:
tangare [24]2 years ago
3 0
It b














Nnsnsmsksksks



Msmmsmskskkskskkskskksksks




Sjsj
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If you had to add two fractions with denominators of 4 and 5. What might the denominator of the sum be? Show more than one possi
mylen [45]

Answer:

your answer would be 20 because you would find what both can go into.

5 0
3 years ago
Can somebody help me & explain ​
Ganezh [65]

Answer:

Step-by-step explanation:

D because it shows that 1x1/3 is shown on # D

5 0
2 years ago
Can I get help with this please
drek231 [11]

Answer:

3)  1 5/6 mi

4)  a. 4 cm, 6 ft

    b. 6.4 cm, 9.6 ft

    c. same as part a

Step-by-step explanation:

3) Each of the given distances appears twice in the sum of side measures that is the perimeter. Hence by walking the perimeter twice, Kyle walks each of the given distances 4 times. His total walk is ...

  4×1/3 + 4×1/8 = 4/3 + 4/8

  = 1 1/3 + 1/2 = 1 2/6 + 3/6

  = 1 5/6 . . . . . miles

___

4) Since the figure is rectilinear (all angles are right angles, and all sides are straight lines), the sum of partial dimensions in one direction is equal to the whole dimension in that direction.

a. 8 cm = 4 cm + x

  8 cm - 4 cm = x = 4 cm

The distance in the room is ...

  (4 cm)×(1.5 ft/cm) = 6 ft

b. 10.3 cm = 3.9 cm + y

  10.3 cm - 3.9 cm = y = 6.4 cm

The distance in the room is ...

  (6.4 cm)×(1.5 ft/cm) = 9.6 ft

c. The answer to part b was obtained in the same way as the answer to part a.  The unknown dimension is the difference of given dimensions. The actual length in the room is the model length multiplied by the inverse of the scale factor.

3 0
3 years ago
Given the set of vertices, determine whether parallelogram ABCD is a rhombus, rectangle or square. List all that apply. A(7,-4),
Sloan [31]

Given:

Vertices of a parallelogram ABCD are A(7,-4), B(-1,-4), C(-1,-12), D(7, -12).

To find:

Whether the parallelogram ABCD is a rhombus, rectangle or square.

Solution:

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula, we get

AB=\sqrt{(-4-(-4))^2+(-1-7)^2}

AB=\sqrt{(-4+4)^2+(-8)^2}

AB=\sqrt{0+64}

AB=8

Similarly,

BC=\sqrt{(-1-(-1))^2+(12-(-4))^2}=8

CD=\sqrt{(7-(-1))^2+(-12-(-12))^2}=8

AD=\sqrt{(7-7)^2+(-12-(-4))^2}=8

All sides of parallelogram are equal.

AC=\sqrt{(-1-7)^2+(-12-(-4))^2}=8\sqrt{2}

BD=\sqrt{(7-(-1))^2+(-12-(-4))^2}=8\sqrt{2}

Both diagonals are equal.

Since, all sides are equal and both diagonals are equal, therefore, the parallelogram ABCD is a square.

We know that, a square is special case of rectangles and rhombus.

So, parallelogram ABCD is a rhombus, rectangle or square. Therefore, the correct option is c.

7 0
2 years ago
What is the distance from point A to point D on the number line?
mrs_skeptik [129]
The answer would be 3.5
7 0
3 years ago
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