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worty [1.4K]
3 years ago
11

Please help quick I have no idea what to do

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
8 0

Answer:

2

Step-by-step explanation:

rise/run 4/2

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(Challenge) Solve this without looking it up.
denis-greek [22]
I have not looked it up, but I did read it a long while ago (about 2 years ago)


albert knows the month
bernard knows the day


first:
albert doesn't know, so his month that he is given must repeat at least once

bernard doesn't know at first, so the day must repeat as well, so it can't be the 19 nor the 16th

the only way for albert to know that bernard doesn't know is that albert must not have been told a month with 16 or 19 in it
that eliminates may and june, leaving july and august

2nd line, now bernard deduces that albert must have been told either july or august
he could not have been told 14 since he would not be able to tell if it was july or august
he was therefor told 15,16, or 17

3rd line:
now albert knows that it is either 15,16,17
notice that july is 16
15 and 17 are both on august
for albert to know what the date is, he must have been told july ( the only one with 1 date on it)


so the birthday is july 16
5 0
3 years ago
What is the scientific notation of 0.0008235
emmasim [6.3K]
That would be 8.235*10^-4
3 0
3 years ago
Read 2 more answers
Use mental math to find the sum.<br> 28 + 65
kogti [31]

Answer:

94 is the answer hope this helps

4 0
3 years ago
Read 2 more answers
The graph of which functions has an axis of symmetry at x = -1/4?
prisoha [69]

Answer:

2x^2 + x - 1

If I did anything you didn't understand let me know so I can explain.  

Step-by-step explanation:

All of them are quadratics so let's use that.

The first one is 2x^2 + x - 1.  To find the axis of symmetry the strategy is usually to find the two zeroes of a quadratic and pick the number between them.  Something to  notice though is that 2x^2 + x - 1 is just 2x^2 + x sshifted down 1, so they both have the same axis of symmetry.  So I am going to ignore the constant, because then finding the zeroes is much much simpler.  I am going to do this with all opions.

So 2x^2 + x - 1 I am just going to use 2x^2 + x.  If you factor out an x you get x(2x + 1)  So now we have it in factored form and we know the zeroes are 0 and -1/2.  The number directly in between these is -1/4, so the axis of symmetry is x = -1/4.  I don't know if there is only one with that axis of symmetry so i am going to check the rest.

2x^2 - x + 1 means we are only going to look at 2x^2 - x.  factoring we get x(2x - 1) so the zeroes are 0 and 1/2, so the axis of symmetry is at 1/4.

x^2 + 2x - 1 we only use x^2 + 2x.  Factored form is x(x+2) so zeroes are 0 and -2 whichh means axis of symmetry is -1

x^2 - 2x + 1 has the same axis of symmetry as x^2 - 2x, which has zeros at 0 and 2 so the axis of symmetry is at 1.

So yep, it was just the first one.

7 0
3 years ago
Read 2 more answers
The image of RST in the graph shown below is rotated 90°counterclockwise around the origin to form R'S'T'.
Aleonysh [2.5K]

Answer:

Please check the explanation.

Step-by-step explanation:

Let suppose we have a point P(x, y) if we rotate our point 90 degrees counterclockwise about the origin, the new coordinates of the image of the point P can be obtained by switching 'x' and 'y' and making 'y' negative.

In other words,

P(x, y) → P'(-y, x)

From the given triangle ΔRST,

The coordinates of the point S is:

  • S(10, 1)

According to the rule, if we have a point S(10, 1), after rotations of 90 degrees counterclockwise about the origin, the new coordinates of the image of the point S(10, 1) will be:

S(10, 1) → S'(-1, 10)

Here,

S'(-1, 10)  is the image of the original point or pre-image point S(10, 1).

Therefore, the y-coordinate of the point S' is: 10

5 0
3 years ago
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