Answer:So, since it is continuously, we need to think of PERT
A=P\times e^{rt}
So, we just plug our numbers in to solve for T
8000=4000e^{.07t}\\\ln(8000)=\ln(4000e^{.07t})\\\ln(8000) = \ln(4000) + \ln(e^{.07t})\\\ln(8000)=\ln(4000)+.07t\ln(e)\\\ln(8000)=\ln(4000)+.07t\\\frac{\ln(8000)}{\ln(4000)}=.07t\\\frac{\ln(8000)}{.07\ln(4000)}=t\\ 15.479=t
It will take 15.479 years
Step-by-step explanation:
Answer:
44 years old
Step-by-step explanation:
Let the age of Jasper be j years old now.
<u>Now</u><u>:</u>
Jasper➣ j
Simon ➣ j/2
<u>1</u><u>2</u><u> </u><u>years</u><u> </u><u>ago</u><u>:</u>
Jasper➣ j -12
Simon➣ j/2 -12
Given that Simon's age=⅕(Jasper's age),
j/2 -12= ⅕(j -12)
<em>Multiply</em><em> </em><em>by</em><em> </em><em>5</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>,</em>
2.5j -60= j -12
2.5j -j= 60 -12
<em>Simplify</em><em>:</em>
1.5j= 48
<em>÷</em><em>1.5</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>
j= 48 ÷1.5
<em>Simplify:</em>
j= 32
<u>12 years time:</u>
Jasper➣ j +12
Thus, Jasper's age
= 32 +12
= 44
Answer:
69
Step-by-step explanation:
term = 159 - 3n
Answer:4x^3-2x^2+20x-10
Step-by-step explanation:
<span>m∠CED = 180° − m∠DEB= 90 degrees, by reason corresponding angles of parallel lines are congruent
</span>m∠CFD = 180° − m∠AFD = 90 degrees by reason corresponding angles of parallel lines are congruent
