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jok3333 [9.3K]
3 years ago
10

Find X 20+4x=28I want to know this answer as it confuses me ​

Mathematics
1 answer:
ser-zykov [4K]3 years ago
6 0

Hey!

--------------------------------------------------

Steps To Solve:

20 + 4x = 28

~Subtract 20 to both sides

20 + 4x - 20 = 28 - 20

~Simplify

4x = 8

~Divide 4 to both sides

4x/4 = 8/4

~Simplify

x = 2

--------------------------------------------------

Hence, the answer is  \Large\boxed{\mathsf{x~=~2}}

--------------------------------------------------

Hope This Helped! Good Luck!

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Zach paid $56.50 including sales tax for a book priced at $45. What was the sales tax rate?
kondaur [170]

Answer:

25.56% or $11.50

Step-by-step explanation:

I took it and put it in a sales tax calc.

3 0
3 years ago
Drag the tiles to the boxes to form correct pairs.<br> Match the pairs of equivalent expressions.
Rashid [163]

Answer:

The following pairs/results are matched:

  • 5\left(2t+1\right)+\left(-7t+28\right) = 3t+33
  • 3\left(3t-4\right)-\left(2t+10\right) = 7t-22
  • \left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right) = \frac{16t}{3}-\frac{23}{5}
  • \left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right) = -\frac{11}{4}t+36

Step-by-step explanation:

Lets solve all the expressions to match the results.

  • 5\left(2t+1\right)+\left(-7t+28\right)

<em>Solving the expression</em>

5\left(2t+1\right)+\left(-7t+28\right)

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

5\left(2t+1\right)-7t+28

10t+5-7t+28

3t+33

Therefore, 5\left(2t+1\right)+\left(-7t+28\right) = 3t+33

  • 3\left(3t-4\right)-\left(2t+10\right)

<em>Solving the expression</em>

3\left(3t-4\right)-\left(2t+10\right)

9t-12-\left(2t+10\right)

9t-12-2t-10

7t-22

Therefore, 3\left(3t-4\right)-\left(2t+10\right) = 7t-22

  • \left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right)

<em>Solving the expression</em>

\left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right)

\mathrm{Remove\:parentheses}:\quad \left(a\right)=a

4t-\frac{8}{5}-\left(3-\frac{4}{3}t\right)

4t-\frac{8}{5}-\left(-\frac{4t}{3}+3\right)

4t-\frac{8}{5}-3+\frac{4t}{3}

As

-3-\frac{8}{5}:\quad -\frac{23}{5}    and  \frac{4t}{3}+4t:\quad \frac{16t}{3}

So,

4t-\frac{8}{5}-3+\frac{4t}{3} will become \frac{16t}{3}-\frac{23}{5}

Therefore, \left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right) = \frac{16t}{3}-\frac{23}{5}

  • \left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right)

<em>Solving the expression</em>

\left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right)

\mathrm{Remove\:parentheses}:\quad \left(a\right)=a

-\frac{9}{2}t+3+\frac{7}{4}t+33

\mathrm{Group\:like\:terms}

\frac{9}{2}t+\frac{7}{4}t+3+33

\mathrm{Add\:similar\:elements:}\:-\frac{9}{2}t+\frac{7}{4}t=-\frac{11}{4}t

-\frac{11}{4}t+3+33

-\frac{11}{4}t+36

Therefore, \left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right) = -\frac{11}{4}t+36

Thus, the following pairs/results are matched:

  • 5\left(2t+1\right)+\left(-7t+28\right) = 3t+33
  • 3\left(3t-4\right)-\left(2t+10\right) = 7t-22
  • \left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right) = \frac{16t}{3}-\frac{23}{5}
  • \left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right) = -\frac{11}{4}t+36

Keywords: algebraic expression

Learn more about algebraic expression from brainly.com/question/11336599

#learnwithBrainly

5 0
3 years ago
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Find the equation of the line through the point (2, 5) that cuts off the least area from the first quadrant. Give your answer us
Amanda [17]

The equation of the line would be

y = mx+b 

where m is the slope, b is the y intercept. 

<span>The line will form a triangular region in the first quadrant. Its area would be 1/2 base times height. The height is the y intercept and the base is y intercept divided by slope. Therefore,</span>

A = b^2/2m

At point (2,5)

5 = 2m+b

Substitute that in the area

A = b^2/5-b to find the least area, differentiate the area with respect to the height and equate it to 0 

dA/db = 0

<span>find b and use that to find m. Then, you can have the equation of the line.</span>


4 0
3 years ago
Read 2 more answers
What is the answer 5i/(2+3i)^2
Nataly_w [17]
Simplify the following:5 i/(3 i + 2)^2
(3 i + 2)^2 = 4 + 6 i + 6 i - 9 = -5 + 12 i:(5 i)/12 i - 5
Multiply numerator and denominator of (5 i)/(12 i - 5) by 5 + 12 i:(5 i (12 i + 5))/((12 i - 5) (12 i + 5))
(12 i - 5) (12 i + 5) = -5×5 - 5×12 i + 12 i×5 + 12 i×12 i = -25 - 60 i + 60 i - 144 = -169:(5 i (12 i + 5))/-169
i (12 i + 5) = -12 + 5 i:(5 5 i - 12)/(-169)
Multiply numerator and denominator of (5 (5 i - 12))/(-169) by -1:Answer: (-5 (5 i - 12))/169
3 0
3 years ago
Wangari plants trees at a constant rate of 1212 trees every 33 hours. Write an equation that relates pp, the number of trees Wan
igor_vitrenko [27]

Answer:

p=4h    

Step-by-step explanation:

Let p be the number of trees Wangari plants, and h  be the time she spends planting them in hours.

We have been given that Wangari plants trees at a constant rate of 12 trees every 3 hours.    

Let us find number of trees planted in 1 hour by dividing 12 by 3.

\text{Number of trees planted in 1 hour}=\frac{12\text{ plants}}{3\text{ hour}}

\text{Number of trees planted in 1 hour}=4\frac{\text{ plants}}{\text{ hour}}

We can represent this information as: p=4h

Therefore, the equation p=4h relates the number of trees (p) Wangari plants, and the time (h) she spends planting them in hours.

3 0
3 years ago
Read 2 more answers
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