Will you please provide more information and state a clear question
solution is (4, - 7 )
given the equations
y = 2x - 15 → (1)
4x + 3y = - 5 → (2)
substitute y = 2x - 15 into (2)
4x + 3(2x - 15) = - 5
4x + 6x - 45 = - 5
10x - 45 = - 5 ( add 45 to both sides )
10x = 40 ( divide both sides by 10 )
x = 4
substitute x = 4 into (1) for corresponding value of y
y = (2 × 4 ) - 15 = 8 - 15 = - 7
solution is (4, - 7 )
Answer: 2.)non function 3.)non function 4.) function 5.)non function 6.) non function 7.)function 8.)non function PART B 1.)non function 2.)function 3.) function
Step-by-step explanation: a function is when the domain (x) all each have one answer like (-2.6)(7,4)(8,6) there can be repeating ranges (y) just not domains.
A non function is when one domain (x) has multiple ranges(y) like (7,2)(-9,6)(7,9) the 7 repeats twice giving it two ranges, which causes it to be non functional. hope that helped :))
Answer:
The value of the slope in this equation is 50
The interpretation is that the rate of change in the cost of the phone bill per unit change in gigabytes of data used each month is 50
Step-by-step explanation:
To answer this question, we need to compare the given equation with the equation of a straight line graph.
The equation we have is;
c = 50g + 75
comparing this with the equation of a straight line, we have
y = mx + c
where m represents the slope and c is the y-intercept
So comparing both, the slope of the equation is 50.
The slope is always the co-efficient of the value on the x-axis
So what does this mean?
The slope also called the gradient represents the rate of change of the y-term divided by the rate of change of the x-term. In simpler terms, when we talk of the slope, we mean the rate of change of the y term per the unit change of the x-term.
So what we mean in this case is the rate of change in cost of the phone bill per unit change in gigabytes of data used each month is 50
Answer:
95% confidence for µ, the average number of times a horse races
(12.493 , 18.107)
Step-by-step explanation:
<u>Explanation</u>:-
The veterinarian finds that the average number of races a horse enters is 15.3
The mean of the sample x⁻ = 15.3
Given standard deviation of the sample 'S' = 6.8
Given sample size 'n' = 25
Degrees of freedom = n-1 =25-1 =24
The tabulated value 't' = 2.064 at two tailed test 0.95 level of significance
<u> 95% confidence for µ, the average number of times a horse races</u>
<u></u>
<u></u>
<u></u>
<u></u>
(15.3 - 2.80704 ,15.3 +2.80704)
(12.493 , 18.107)
<u>Conclusion</u>:-
95% confidence for µ, the average number of times a horse races
(12.493 , 18.107)
