3/x-3+x/x+3
3(x+3)+x(x-3)/(x-3)(x+3)
3x+9+x^2-3x/(x-3)(x+3)
x^2+9/X^2-9
I can’t figure out what your trying to say
Alright because of P.E.M.D.A.S we want to start with the paranthesis but there is nothing we can do so we move on to exponents.
4^2 is 16
16(20-×)-8(x+3)=8 we need to distribute the numbers in front of the paranthesis across both number inside them.
320-16x-8x-24=8
now combine like terms
296-24x=8
now we need to isolate the variable so subtract 296 from both sides.
-24x=-288
now divide both sides by -24
x= 12