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Wittaler [7]
3 years ago
13

How is the function f(x) related to the function g(x)

Mathematics
1 answer:
jasenka [17]3 years ago
8 0

Answer:

Option 3. f(x) is g(x) stretched vertically by a factor 8 and reflected about the x axis.

Step-by-step explanation:

The given functions are F(x) = -\frac{1}{2} sin5x----(1)

and g(x) = 4sin5x ------(2)

In the function (1)

F(x) = -\frac{1}{2} sin5x

Amplitude A = \frac{1}{2}

In the function (2)

g(x) = 4sin5x Amplitude A' = 4

So when we compare these graphs we get

\frac{A'}{A}=\frac{4}{\frac{1}{2} }\frac{A'}{A}= (\frac{4}{1})(\frac{2}{1})

A' = 8A

Since the Graph number (2) is of positive sign that means Graph (1) is reflected about the x axis to get (2)

Therefore Option 3 is correct f(x) is stretched vertically by a factor of 8 and reflected by X axis


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X^2 - y^2 = 100
luda_lava [24]

Answer:

20

Step-by-step explanation:

Let's start by rewriting the second equation in terms of "x":

x+y=5

Subtract y from both sides:

x=5-y

Now, substitute "5-y" for "x" in the first equation:

(5-y)^2-y^2=100

Note that:

(a-b)^2=a^2-2ab+b^2

25-10y+y^2-y^2=100

Cancel out like terms:

25-10y=100

Subtract 25 from both sides:

-10y=75

Divide both sides by -10

y=\frac{75}{-10}=\frac{15}{-2}=-\frac{15}{2}

Now, substitute this value back into either of the equations to solve for x.

x+y=5\\x-\frac{15}{2}=5\\

Add 15/2 to both sides:

x=5+\frac{15}{2}\\x=\frac{10}{2}+\frac{15}{2}\\x=\frac{25}{2}

Now, find the difference:

x-y=\frac{25}{2}-(-\frac{15}{2})=\frac{25}{2}+\frac{15}{2}=\frac{40}{2}=20

8 0
2 years ago
The angle between the minute hand and the hour hand of a clock is 90 degrees. What time is it? Justify your answer.
tangare [24]
If it is exactly 90 degrees you are looking for, your answer would be, 3:0:0. Which is 3:00.
3 0
3 years ago
What two rational expressions sum to 3x+4/x^2-6x+5?
Lubov Fominskaja [6]

Answer:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

Step-by-step explanation:

The given rational expression is:

\frac{3x+4}{x^{2}-6x+5} = \frac{3x+4}{(x-1)(x-5)}

We can use concept of Partial Fractions to solve this problem. Let,

\frac{3x+4}{(x-1)(x-5)}=\frac{A}{x-1} +\frac{B}{x-5}

Multiplying both sides by (x - 1)(x - 5), we get:

3x+4=A(x-5)+B(x-1)

Substituting x = 5, we get:

3(5)+4=A(5-5)+B(5-1)\\\\ 15+4=0+4B\\\\ 19=4B\\\\ B=\frac{19}{4}

Substituting x = 1, we get:

3(1)+4=A(1-5)+B(1-1)\\\\ 7=-4A\\\\ A=-\frac{7}{4}

Substituting the value of A and B, back in the original equation, we get:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

4 0
3 years ago
800 is 10 times as much as what
Margaret [11]
800 is 10 times as much as 80
8 0
3 years ago
What is the sum of the first 10 terms in the geometric sequence -3 6 -12 24 -48
vlada-n [284]
Use the formula for the sum of a geometric sequence:
Sum = (a(r^n - 1))/(r - 1)
where a is the first term, -3
r is the common ratio, -2
and n is the number of terms

Thus,
Sum = ((-3)((-2)^10 - 1))/(-2-1) = 1023
3 0
3 years ago
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