2 normal types of sequences:
1. arythmetic sequences: each term is the same distance to the next term, example, 2,4,6,8, distance is 2
2. geometric sequences: the ratio of consecutive terms is the same, example: 2,4,8,16, ratio is 4:2=2:1, 2/1=2
the nth term is denoted by

the first term is represented by

for arythmetic sequences, the nth tem is

where d=distance between each term
for geometric sequences the nth term is
[tex] a_{n}=a_{1}r^{n-1} where r=ratio betwen consecutive terms
2/5=6/15 and that is less than 7/15
Step-by-step explanation:
Number 3
cos∅ = adj/hyp
cos35° = 20/x
x = 20/cos35°
x = 20/0.8192
x = 24.4155
x ≈ 24.4 to the nearest tenth
Option C
Number 6
tan∅ = opp/adj
tan37° = 20/x
x = 20/tan37°
x = 20/0.7536
x = 26.5409
x ≈ 26.5 to the nearest tenth
Option B
Answer:
a) 25.15
b)
x = 1
y = t
z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)
c) (x,y) = (1, -2pi)
Step-by-step explanation:
a)
First lets calculate the velocity, that is, the derivative of c(t) with respect to t:
v(t) = (-sin(t), cos(t), 2t)
The velocity at t0=4pi is:
v(4pi) = (0, 1, 8pi)
And the speed will be:
s(4pi) = √(0^2+1^2+ (8pi)^2) = 25.15
b)
The tangent line to c(t) at t0 = 4pi has the parametric form:
(x,y,z) = c(4pi) + t*v(4pi)
Since
c(4pi) = (1, 0, (4pi)^2)
The tangent curve has the following components:
x = 1
y = t
z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)
c)
The intersection with the xy plane will occurr when z = 0
This happens at:
t1 = -2pi
Therefore, the intersection will occur at:
(x,y) = (1, -2pi)
Answer:
24
Step-by-step explanation:
Solve for x by simplifying both sides of the equation, then isolating the variable.
x=24