Question

Arthur can throw a ball twice as far as Beatrice. Beatrice can throw a ball one-third as far as Cory. Cory can throw a ball twice as far as Dominick. What is the ratio of the distance of Arthur's throw to Dominicks throw? Detailed answer please!

Answer 1

Answer:

A : D

4 : 3

Step-by-step explanation:

We'll use the first letter of their names as the heading for the ratio.

The first line states:

A : B

2 : 1

The second line states:

B : C

1/3 : 1

The third line states:

C : D

2 : 1

We have three different ratios but we know that they are related to one another so we are going to combine them by equating the common ratio of the different ratios.

Let's look at the ratio with a fraction first.

B : C

1/3 : 1

If we ×3 throughout, this can also be written as:

B : C

1 : 3

Now B in the first and second ratio is the same number and we are able to combine them. We can write them all together like this:

A : B : C

2 : 1 : 3

In the third ratio, C is 2, however in the ratio we have now C is 3. We can make them the same number by ×3 throughout the third ratio and ×2 throughout the ratio we have now.

C : D

2 : 1

6 : 3

A : B : C

2 : 1 : 3

4 : 2 : 6

We can see that our ratio for C is the same number and we can now combine the ratios.

A : B : C : D

4 : 2 : 6 : 3

The question asked for A : D so we can take just the values of A and D.

A : D

4 : 3

I hope this helps :)