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marysya [2.9K]
3 years ago
12

PLZZZZ I NEED HELP ASAP!!!!

Physics
1 answer:
Leya [2.2K]3 years ago
5 0
I believe Alfred Wegener would be much more succesful today.
Alfred wegener presented his continental drift hypothesis in 1912, and his idea was dismissed back then (he died in 1930s.)
But after entering 1950s, many scientists started to accepted the idea of the continental drift, which means that the scientific community just only accepted his idea 20 years after his death.
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Defination of radiation​
saw5 [17]

Answer:

the emission of energy as electromagnetic waves or as moving subatomic particles, especially high-energy particles which cause ionization.

Explanation:

6 0
3 years ago
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A small pebble and one large boulder start at the same height and begin rolling down the side of a mountain. Which object would
vitfil [10]

Answer:

The small pebble

Explanation:

Since the potential energy, P.E lost equals kinetic energy, K.E gained,

P.E = K.E

P.E = mgh = K.E

So, K.E = mgh where g = acceleration due to gravity and h = height of drop

Since h and g are constant

K.E ∝ m

So, the kinetic energy of the object is directly proportional to its mass. Thus, the object with the smaller mass has the lesser kinetic energy.

Since the object with the smaller mass is the small pebble, so the small pebble would have less kinetic energy as it crashes on the road at the bottom of the mountain.

8 0
3 years ago
When a burning stick of increase is moved fast in a circle a circle of red light is seen.​
anzhelika [568]

Answer:

The impression of the image on the retina lasts for about 1/16th of a second after the removal of the object. If a burning stick of incense is revolved at a rate of more than sixteen revolutions per second, we see a circle of red light due to persistence of vision.

Explanation:

7 0
3 years ago
There is a 50 g sample of Ra-229. It has a half-life of 4 minutes.
Sloan [31]

Via half-life equation we have:


A_{final}=A_{initial}(\frac{1}{2})^{\frac{t}{h} }


Where the initial amount is 50 grams, half-life is 4 minutes, and time elapsed is 12 minutes.  By plugging those values in we get:

A_{final}=50(\frac{1}{2})^\frac{12}{4}=50(\frac{1}{2})^{3}=50(\frac{1}{8})=6.25g


There is 6.25 grams left of Ra-229 after 12 minutes.

4 0
4 years ago
Question 8 of 10
Alika [10]
B. Venus hope this helps have a great day
6 0
3 years ago
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