All categories

3 years ago

According to the three laws of planetary motion, planetary orbits are in the shape of a/an

1 answer:

8 0

<span>According to the three laws of planetary motion, planetary orbits are in the shape of an "Ellipse"

In short, Your Answer would be Option B

Hope this helps!</span>

You might be interested in

As an object falls freely near the surface of the earth, its velocity?

Vsevolod [243]

If it were possible for an object to fall freely near the surface of the Earth,

-- The direction of its velocity would always be "down"; that is, toward the center of the Earth.

-- The size of its velocity would continually increase, at the rate of 9.8 meters per second for every second it falls.

7 0

3 years ago

Beers of snakes thunderstorms darkness in water are classified as blank phobias

Scrat [10]

I believe all of these would be known as specific phobias.

4 0

3 years ago

On what two properties of a material does its density depend on?

ExtremeBDS [4]

Density of a material depends upon it's mass & volume.

You can calculate it by: Density = Mass / Volume

Hope this helps!

4 0

3 years ago

A useful tool for recoding observations for later analysis is a. This is for science

Gnoma [55]

What type of recording device? You can have a: camera and voice recorder, these are the only type of recording device I can think of

There may be more, but these are the ones I think you are allowed... hope this helps you ☁︎☀︎☁︎

5 0

3 years ago

A 14.0 gauge copper wire of diameter 1.628 mmcarries a current of 14.0 mA. Part A: What is the potential difference across a 2.1

FrozenT [24]

Answer:

for copper potential difference is 2.4871 × $10^{-4}$ V

for silver potential difference is 2.1256 × $10^{-4}$ V

Explanation:

given data

diameter D = 1.628 mm = 0.001628 m

current = 14.0 mA = 0.0140 A

length L = 2.15 m

to find out

potential difference

solution

we consider here

resistivity of silver = 1.47 × $10^{-8}$ ohm-m

resistivity of copper = 1.72 × $10^{-8}$ ohm-m

so we apply here resistance formula that is

Resistance = ρ × L / A ...............1

so here area A = πr² = π(0.001628 /2)² = 2.0816 × $10^{-6}$ m²

for copper Resistance = ρ × L / A

Resistance = 1.72 × $10^{-8}$ × 2.15 / 2.0816 × $10^{-6}$

Resistance = 1.7765 × $10^{-2}$ ohm

for silver Resistance = ρ × L / A

Resistance = 1.47 × $10^{-8}$ × 2.15 / 2.0816 × $10^{-6}$

Resistance = 1.5183 × $10^{-2}$ ohm

potential difference is calculated as

for copper potential difference = current × resistance

potential difference = 0.0140 ×1.7765 × $10^{-2}$

potential difference = 2.4871 × $10^{-4}$ V

for silver potential difference = current × resistance

potential difference = 0.0140 × 1.5183 × $10^{-2}$

potential difference = 2.1256 × $10^{-4}$ V

7 0

3 years ago