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babymother [125]

3 years ago

6

A wheel initially has an angular velocity of 18 rad/s, but it is slowing at a constant rate of 2 rad/s 2 . By the time it stops,

it will have turned through approximately how many revolutions?

1 answer:

Kaylis [27]3 years ago

3 0

Answer:13 revolution

Step-by-step explanation:

Given data

Wheel initial angular velocity $\left ( \omega \right )$ =18 rad/s

Contant angular deaaceleration $\left ( \alpha \right )$ =2 $rad/s^2$

Time required to stop wheel completely=t sec

$\omega =\omega_0 + \aplha t$

0 =18 + $\left ( -2\right )t$

t=9 sec

Therefore angle turn in 9 sec

$\theta$ = $\omega_{0} t$ + $\frac{1}{2}$ $\left ( \alpha\right )t^{2}$

$\theta$ = $18\times 9$ + $\frac{1}{2}$ $\left ( -2\right )\left ( 9\right )^2$

$\theta$ =81rad

therefore no of turns(n) = $\frac{81}{2\times \pi}$

n=12.889 $\approx$ 13 revolution

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Answer:

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Step-by-step explanation:

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3 years ago

In an isolated environment, a disease spreads at a rate proportional to the product of the infected and non-infected populations

eimsori [14]

Answer:

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Step-by-step explanation:

First, gather the information:

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N₀ = K

20 = K

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Step-by-step explanation:

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3 years ago

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Nookie1986 [14]

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Step-by-step explanation:

Given,

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Keywords: multiplication, linear expression

Learn more about multiplication at:

#LearnwithBrainly

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3 years ago