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dezoksy [38]
3 years ago
9

Silvia wants to retire at 65 and live on 40,000 a year. How much does she need to save to ensure that her retiement funds last u

ntil she is 85?
A.) $800,000 because she will need to save for 20 years times 40,000.

B.) More than 800,000 because taxes and inflation will increase that value of her savings.

C.) Less than 800,000 because returns will continue to increase the amount in her savings even after retirement.

D.) More than 800,000 because compound return will reduce her savings
Mathematics
1 answer:
ExtremeBDS [4]3 years ago
4 0

Answer:

A If this is maths!!!

Step-by-step explanation:

If we rely solely on mathematics then the answer must be A. The other options seem to be from economy so it has nothing with mathematics. Please make sure that this is math task then answer.

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Prove that Associative property does not hold true for 8 / 9 – ( 9 / 10 – 2 / 5 )
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I think the answer above is correct
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Ethan’s car averages 22 miles per gallon of gas. Predict how far he can travel on 5 gallons of gas.
Andru [333]

Answer:

110 have a good one

Step-by-step explanation:

22x5 is 110

4 0
3 years ago
Are these right?!?! Cannot fail
jolli1 [7]
The first one is correct but I don’t know about the second one
4 0
3 years ago
A has the coordinates (–4, 3) and B has the coordinates (4, 4). If DO,1/2(x, y) is a dilation of △ABC, what is true about the im
loris [4]

Answer:

Coordinates of Vertices of triangle ABC are A (-4,3) , B(4,4) and C(1,1).

As, DO is Dilation of Δ ABC by Scale factor of \frac{1}{2}.

Vertices of A' B'C' are

A'=(\frac{-4}{2},\frac{3}{2})=(-2,\frac{3}{2}), B'=(\frac{4}{2},\frac{4}{2})=(2,2), C'=(\frac{1}{2},\frac{1}{2})

So, Image Δ A'B'C' will be smaller than the Pre image Δ ABC.

The two triangles will be congruent.

AO is Dilated by a factor of half , so A'O' will be half of AO.

So, correct Statements are

1. AB is parallel to A'B'.

2.DO,1/2(x, y) =  

The distance from A' to the origin is half the distance from A to the origin.

OA=\sqrt{(-4)^2+3^2}=\sqrt{25}=5\\\\ O'A'=\sqrt{2^2+(\frac{3}{2})^2}=\frac{5}{2}=2.5

8 0
3 years ago
Read 2 more answers
Find the area lying above the x-axis and below the parabolic curve y = 4x -x2 A. 8 B. 16 C. 10 2/3 D. 8 1/3
dimaraw [331]
To find the area between the x-axis and the parabolic curve, take the integral of the area in which the curve is above the x-axis.
function of the graph is
y = 4x - x²
We can tell by the function (specifically -x²) that the parabola will point downward.
To find the domain in which y>0, let's find the roots (0's) of the function:
0 = 4x - x²
0 = x (4 - x) 
x = 0 or x = 4
Between x=0 and x=4, the curve is above the x-axis. To find the area of the graph, let's take the integral on this range:

First, take the antiderivative of 4x - x²:
2x² - (1/3) x³
Then, plug x=4 into the anti-derivative, and subtract the anti-derivative at x=0:
2(4)² - (1/3)(4³) - (0 - 0)
32 - 64/3
96/3 - 64/3 = 32/3 

Closest Answer is C) 10
7 0
3 years ago
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