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timurjin [86]
3 years ago
14

4)

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
5 0

Answer:

|-9| = 9

That is the absolute value for the loss of yards

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Can someone plz help me with this
slava [35]

Answer:

Step-by-step explanation:

2a. f(-3) = (-3)^2-4(-3)+6 = 9+12+6 = 27

2b. f(-2) = 3(-2)^2-(-2)^3 -2 +1 = 3(4) - (-8) -2 +1

= 12+8-1 = 19

8 0
2 years ago
Please help me with this answer!! I am really stuck...No nonsense answers please.
wariber [46]

Answer:

19

Step-by-step explanation:

Inscribed Angle = 1/2 Intercepted Arc

< DBG = 1/2 ( DG)

< DBG = 1/2 ( 360 - BD - BG)

           = 1/2 ( 360 - 172 - 150)

           = 1/2 (38)

           = 19

8 0
3 years ago
What is this number in standard form? <br> (8×100)+(4×1)+(6×1100)+(3×11,000)
Korvikt [17]

Answer:

40404

Step-by-step explanation:

is this helpful????

5 0
2 years ago
Read 2 more answers
Describe how to find the Greatest common factor if two numbers by using prime factorization
gizmo_the_mogwai [7]
To find the greatest common factor using prime factorization by only using prime number divided into the dividend then you continue til it reaches 1 then the prime factorization would look like this e.g. 2×3×5×11
6 0
3 years ago
SOMEONE HELP ME IM FREAKING OUT I LITERALLY CANT WITH THIS QUESTION IM PRAYING PLEASE HELP ME IM SO SERIOUS IM GONNA END IT PLS
antiseptic1488 [7]

Answer:

\sf -11+7\sqrt{2}

Step-by-step explanation:

Given expression:

\sf \dfrac{3-\sqrt{32}}{1+\sqrt{2} }

Rewrite 32 as 16 · 2:

\sf \implies \dfrac{3-\sqrt{16 \cdot 2}}{1+\sqrt{2} }

Apply radical rule \sf \sqrt{a \cdot b}=\sqrt{a}\sqrt{b}

\sf \implies \dfrac{3-\sqrt{16}\sqrt{2}}{1+\sqrt{2} }

As \sf \sqrt{16}=4:

\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} }

Multiply by the conjugate:

\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} } \times \dfrac{1-\sqrt{2} }{1-\sqrt{2} }

\sf \implies \dfrac{(3-4\sqrt{2})(1-\sqrt{2})}{(1+\sqrt{2})(1-\sqrt{2})}

\sf \implies \dfrac{3-3\sqrt{2}-4\sqrt{2}+4\sqrt{2}\sqrt{2}}{1-\sqrt{2}+\sqrt{2}-\sqrt{2}\sqrt{2}}

As \sf \sqrt{2}\sqrt{2}=\sqrt{4}=2:

\sf \implies \dfrac{3-3\sqrt{2}-4\sqrt{2}+4 \cdot 2}{1-\sqrt{2}+\sqrt{2}-2}

\sf \implies \dfrac{3-7\sqrt{2}+8}{1-2}

\sf \implies \dfrac{11-7\sqrt{2}}{-1}

\sf \implies -11+7\sqrt{2}

7 0
2 years ago
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