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11Alexandr11 [23.1K]
3 years ago
9

-7y-4x=1 and 7y-2x=53 solve the system of equation

Mathematics
1 answer:
djverab [1.8K]3 years ago
3 0
The answer is x=-9 and y=5
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Please, can someone help me?
irina [24]

Step-by-step explanation:

4. not enough information

5.SAS

.we have PE congruent to ER

.angle PEF congruent to angle FER

.and EF that is common for both of triangles

6.SSS

.MO congruent to KL

.MK congruent to OL

.KO that is common for both of triangles.

5 0
3 years ago
miles wants some new games for his phone. each game costs 2.99 how much would it cost if he bought 7 new games
bekas [8.4K]

Answer: $20.93

Step-by-step explanation:

If you take a game that costs $6.99, and then multiplied that by 7, you would get $20.93.

Let me know if this helps!!!

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6 0
3 years ago
Read 2 more answers
Y=x^2-2x-1 and y=-3x+5 solved algebraically
eduard

Answer:

Step-by-step explanation:

y=x²-2x-1

and y=-3x+5

x²-2x-1=-3x+5

x²+x-6=0

x²+3x-2x-6=0

x(x+3)-2(x+3)=0

(x+3)(x-2)=0

x=-3,2

when x=-3

y=-3×-3+5=9+5=14

when x=2

y=-3×2+5=-6+5=-1

so solutions are (-3,14) and (2,-1)

3 0
3 years ago
Reflect (10,-8) over the x-axis
cricket20 [7]

Answer:

(10,8)

Step-by-step explanation:

Symmetry over x axis: you keep x, but change the sign of y value.

So, the symmetric of (10,-8) is (10,8)

3 0
3 years ago
Can atriangle be formed with side lengths of 5cm. 10cm and 15cm
andreyandreev [35.5K]
Theorem of cosine:
a²=b²+c²-2bc(cos α)  ⇒cos α=-(a²-b²-c²) / 2bc

In this case:
a=15 cm
b=10 cm
c=5 cm

cos α=-(15²-10²-5²) / 2*10*5
cos α=-100 / 100
cos α=-1

A=arc cos -1=180º  This is impossible, because:

A+B+C=180º; then  B=C=0º  This is impossible for make a triangle  (B>0 and C>0 if we want to make a triangle).  

Therefore: it is not possible can make a triangle with side lengths of 5 cm, 10 cm and 15 cm.

3 0
3 years ago
Read 2 more answers
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