Let f(x) = p(x)/q(x), where p and q are polynomials and reduced to lowest terms. (If p and q have a common factor, then they contribute removable discontinuities ('holes').)
Write this in cases:
(i) If deg p(x) ≤ deg q(x), then f(x) is a proper rational function, and lim(x→ ±∞) f(x) = constant.
If deg p(x) < deg q(x), then these limits equal 0, thus yielding the horizontal asymptote y = 0.
If deg p(x) = deg q(x), then these limits equal a/b, where a and b are the leading coefficients of p(x) and q(x), respectively. Hence, we have the horizontal asymptote y = a/b.
Note that there are no obliques asymptotes in this case. ------------- (ii) If deg p(x) > deg q(x), then f(x) is an improper rational function.
By long division, we can write f(x) = g(x) + r(x)/q(x), where g(x) and r(x) are polynomials and deg r(x) < deg q(x).
As in (i), note that lim(x→ ±∞) [f(x) - g(x)] = lim(x→ ±∞) r(x)/q(x) = 0. Hence, y = g(x) is an asymptote. (In particular, if deg g(x) = 1, then this is an oblique asymptote.)
This time, note that there are no horizontal asymptotes. ------------------ In summary, the degrees of p(x) and q(x) control which kind of asymptote we have.
I hope this helps!
0x39=n
anything times zero = zero so that mean n = 0
Ans: Sunny Market
Sunny Market as $3.20/5=$0.64 while and
Happy Mart $1.58/2=$0.79
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<u><em>Answer:</em></u>sin (C)
<u><em>Explanation:</em></u><u>In a right-angled triangle, special trig functions can be applied. These functions are as follows:</u>
sin (theta) = </span>

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cos (theta) = </span>

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tan (theta) = </span>

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<u>Now, let's check the triangle we have:</u>
<u>We have two options:</u>
<u>First option:</u>5 is the hypotenuse of the triangle
4 is the side adjacent to angle B
Therefore, we can apply the <u>cos function</u>:
cos (B) = </span>

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<u>Second option:</u>5 is the hypotenuse of the triangle
4 is the side opposite to angle C
Therefore, we can apply the <u>sin function</u>:
sin (C) = </span>

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Among the two options, the second one is the one found in the choices. Therefore, it will be the correct one.
Hope this helps :)
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The length is 9.
The formula to find the perimeter of a rectangle is
2L + 2W = P.
2L + 2(4) = 26.
2L + 8 = 26.
2L + 8 (-8) = 26 (-8).
2L = 18.
2L/2 = 18/2.
L = 9.