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3 years ago

Solve for xx. Leave your answer in simplest radical form.

Mathematics

1 answer:

never [62]3 years ago

5 0

This answer is 76 let me know if I’m wrong

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If f(x) = 2x + 6 and g(x) = -4x - 8 find f(g(x)) = ?x+?

amm1812

hope it helps

plz mark brainliest

6 0

3 years ago

Order these fractions from least to greatest 24/9 5/9 15/9 15/9 9/9

Angelina_Jolie [31]

5/9, 9/9, 15/9, 15/9, 24/9. hope this helped.

6 0

3 years ago

Read 2 more answers

Answer choice (A)5/30 (B)3/17 (C) 8/30 (D) 16/30

ratelena [41]

<h3>Answer: (C) 8/30</h3>

===================================================

Explanation:

There are 5+3 = 8 people in choir and running club. I added the values in the overlapped region of the circles "choir" and "running club".

This is out of 2+5+6+7+3+4+3 = 30 people total.

Divide the two results to form the fraction 8/30

Ideally we should reduce to get 4/15, but your teacher has chosen not to reduce.

8 0

3 years ago

Simultaneously x-2y=0 40-y=14

harkovskaia [24]

Answer:

x = 52, y = 26

Step-by-step explanation:

x - 2y = 0

40 - y = 14

(40 - 40) - y = 14 - 40

- y = -26

y = 26

x - 2(26) = 0

x - 52 = 0

x (- 52 + 52) = 0 + 52

x = 52

7 0

3 years ago

I really really really need help!!!!

Yakvenalex [24]

For $f$ to be continuous at $x=1$ , you need to have the limit from either side as $x\to1$ to be the same.

$\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^-}(|x-1|+2)=2$
$\displaystyle\lim_{x\to1^+}f(x)=\lim_{x\to1^+}(ax^2+bx)=a+b$

If $a=2$ and $b=3$ , then the limit from the right would be $2+3=5\neq2$ , so the answer to part (1) is no, the function would not be continuous under those conditions.

This basically answers part (2). For the function to be continuous, you need to satisfy the relation $a+b=2$ .

Part (c) is done similarly to part (1). This time, you need to limits from either side as $x\to2$ to match. You have

$\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2^-}(ax^2+bx)=4a+2b$
$\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2^+}(5x-10)=0$

So, $a$ and $b$ have to satisfy the relation $4a+2b=0$ , or $2a+b=0$ .

Part (4) is done by solving the system of equations above for $a$ and $b$ . I'll leave that to you, as well as part (5) since that's just drawing your findings.

8 0

3 years ago