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3 years ago

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The grades on the last history exam had a mean of 75%. Assume the population of grades on history exams is known to be normally

distributed with a standard deviation of 7. What percent of students earn a score between 70% and 82%?

1 answer:

RUDIKE [14]3 years ago

6 0

34% . <span>Since going from 75% to 82% is simply the right portion of that middle, the answer is half of 68%, or 34%.</span>

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simplify the following expression: (x+7/4x) + (5/x-8) I also attached a photo of the problem if you get confused on how I typed

Gnoma [55]

Answer:

$\frac{x^{2} + 19x - 56}{4 {x}^{2} - 32x}$

Step-by-step explanation:

Start by making the denominators of both fraction the same. This can be done by multiplying one fraction's denominator by the other.

After simplifying and combining the two fractions together, check if the numerator can be factorised such that there is a common factor in the denominator and numerator. In this case, the numerator cannot be factorised.

Lastly, expand the denominator.

$\frac{x + 7}{4x} + \frac{5}{x - 8}$

$= \frac{(x + 7)(x - 8)}{4x(x - 8)} + \frac{5(4x)}{4x(x - 8)}$

$= \frac{x(x) + x( - 8) + 7(x) + 7( - 8) + 20x}{4x(x - 8)}$

$= \frac{ {x}^{2} - 8x + 7x - 56 + 20x }{4x(x - 8)}$

$= \frac{ {x}^{2} + 19x - 56}{4x(x - 8)}$

$= \frac{ {x}^{2} + 19x - 56}{4 {x}^{2} - 32x}$

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SVETLANKA909090 [29]

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