X= number of student tickets
Y= number of on student tickets
x+y=311
0.50x + 1.50y = 385.50
Solve x in 1st equation
X+y=311
X= -y + 311
Now substitute x into second equation to solve for y
0.50(-y+311)+ 1.50y = 385.50
-0.50y+311.50+1.50y=385.50
Y+311.50=385.50
Y= 385.50-311.50
Y= 74
Now substitute y answer to first equation to find x
X+y=311
X+ 74=311
X= 311-74
X= 237
So 237 students tickets and 74 non students tickets
The first thing to do is to work out the biggest number that goes into bother 24 and 3. As the only that goes into three- other than 1- is itself, one can assume this is the number we are looking for.
Next, divide bother numbers by 3.
24 / 3 = 8
3 / 3 = 1
You now take 3 out of the brackets, and leave 8 and 1. 24x / 3 = 8x.
3(8x + 1)
Week 4
you can see that the dots are the closest
What are the sides of the rectangular prisms ?
To find the number of non-defective chips, we simply use this equation:
2,000 * 4/5
8000/5
Now you simply divide:
1600
1600 chips aren't defective