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3 years ago

PLEASE HELP WITH MATH.BEST ANSWER GETS BRAINLIEST. You have to find the volume of the figure below.

Mathematics

1 answer:

castortr0y [4]3 years ago

6 0

Volume = width × height × length. First let's concentrate on the rectangular prism. This has 4 for its height and 5 for its width so you do 4 × 5 (=20) × 10 (because the length of the rectangular prism is the same as the triangular prism, so we will use the length of the triangular one) = 200m³ for the rectangular one. To work out the triangular one, it's the same, but whatever answer you get you divide it by 2 because a triangle is just a rectangle cut in half diagonally. Therefore, 3 × 5 (=15) × 10 = 150. Then divided by 2 = 75m³. Total volume = volume of rectangular prism + triangular prism Therefore total volume = 200 + 75 = 275m³.

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Write an equation of the line that passes through the point (-6, -9) with slope-5.

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Answer:

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Step-by-step explanation:

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In this case, the slope is -5 and the point is $(-6,-9)$ so the equation will be:

$y+9=-5(x+6)$

Want to learn more about point-slope form? Check the link out:

https://www.albert.io/blog/point-slope-form/#What_is_point_slope_form

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3 years ago

At the craft store, Tara bought 12 yards of fabric to make tote bags. Each bag requires 1.25 yards of fabric. If Tara makes 5 to

matrenka [14]

Answer:

5.75 yds left

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1.25 yds per bag*5 bags =6.25 yds used

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2 years ago

In ΔKLM, the measure of ∠M=90°, LK = 97, ML = 65, and KM = 72. What is the value of the sine of ∠L to the nearest hundredth?

Sphinxa [80]

Answer:

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3 years ago

What is the greatest common factor of 4k, 18k4, and 12?

Setler [38]

Answer: The greatest common factor is 2.

Step-by-step explanation: We are given to find the greatest common factor of the following expressions:

$E_1=4k,~~E_2=18k^4,~~E_3=12.$

<u>Greatest Common Factor:</u> The GCF of two or more numbers (expressions) is the greatest factor that divides all the numbers or expressions.

We have

$E_1=4k=2\times 2\times k,\\\\E_2=18k^4=2\times 3\times 3\times k\times k\times k\times k,\\\\E_3=12=2\times 2\times 3.$

Therefore, the greatest common factor will be

$G.C.F.=2.$

Thus, the required greatest common factor is 2.

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