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fomenos
3 years ago
7

How do you solve this problem 11-4x+6x-15=-14

Mathematics
1 answer:
Radda [10]3 years ago
7 0

Answer:

x = -5

Step-by-step explanation:

Solve for x, add/subtract like term.

11 - 4x + 6x - 15 = -14

Here like terms are

-4x and 6x

11, - 15 and -14


11 - 4x + 6x - 15 = -14

2x - 4 = -14

2x = -14 + 4

x = -10 / 2

x = -5

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<span>Let be A =a3b +9a2b2-4ab5, and B=a3b-3a2b2+ab5,so the difference can be defined as A - B =a3b +9a2b2-4ab5 -(a3b-3a2b2+ab5), when there is negative sign in front of the parathesis, all the inside signs must change: that is as follow: A- B= a3b +9a2b2-4ab5 - a3b + 3a2b2 - ab5= a3b-a3b +9a2b2+3a2b2-4ab5- ab5= 12a2b2 -5ab5, the fist term has 2+2=4, as a degree,the second term has 1 +5 =6, so the true answer : The difference is a binomial with a degree of 6</span>
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4 years ago
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Write the six terms of each arithmetic sequencePlease see picture for question
chubhunter [2.5K]

ANSWER

The six terms for the arithmetic sequence is 1.6, 1.2, 0.8. 0.4, 0, -0.4

EXPLANATION

Given that;

\begin{gathered} a_n\text{ = a}_{n\text{ - 1}}\text{ - 0.4} \\ \text{ a}_1\text{ = 1.6} \end{gathered}

To find the second term, let n = 2

\begin{gathered} \text{ a}_2\text{ }=\text{ a}_{2\text{ - 1}}\text{ - 0.4} \\ \text{ a}_2\text{ }=\text{ a}_1\text{ - 0.4} \\ \text{ a}_1\text{ = 1.6} \\ \text{ a}_2\text{ }=\text{ 1.6 - 0.4} \\ \text{ a}_2\text{ }=\text{ 1.2} \end{gathered}

To find the third term, let n = 3

\begin{gathered} \text{ a}_3\text{ }=\text{ a}_{3\text{ - 1}}\text{ - 0.4} \\ \text{ a}_3\text{ }=\text{ a}_2\text{  - 0.4} \\ \text{ a}_2\text{ = 1.2} \\ \text{ a3 }=\text{ 1.2 - 0.4} \\ \text{ a}_3\text{ = 0.8} \end{gathered}

To find the fourth term, let n = 4

\begin{gathered} \text{ a}_4\text{ }=\text{ a}_{4-\text{ 1}}\text{ - 0.4} \\ \text{ a}_4\text{ = a}_3\text{ - 0.4} \\ \text{ a}_3\text{ = 0.8} \\ \text{ a}_4\text{ = 0.8 - 0.4} \\ \text{ a}_4\text{ = 0.4} \end{gathered}

To find the fifth term, let n = 5

\begin{gathered} \text{ a}_5\text{ = a}_{5\text{ - 1}}\text{ - 0.4} \\ \text{ a}_5\text{ }=\text{ a}_4\text{ - 0.4} \\ \text{ a}_4\text{ = 0.4} \\ \text{ a}_5\text{ = 0.4 - 0.4} \\ \text{ a}_5\text{ = 0} \end{gathered}

To find the 6th term, let n = 6

\begin{gathered} \text{ a}_6\text{ }=\text{ a}_{6\text{ - 1}}\text{ - 0.4} \\ \text{ a}_6\text{ = a}_5\text{ - 0.4} \\ \text{ a}_5\text{ = 0} \\ \text{ a}_6\text{ = 0 - 0.4} \\ \text{ a}_6\text{ = -0.4} \end{gathered}

Hence, the six terms for the arithmetic sequence is 1.6, 1.2, 0.8. 0.4, 0, -0.4

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