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3 years ago

Name the first five terms of each arithmetic sequence described an=7+5(n-1)

Mathematics

1 answer:

Butoxors [25]3 years ago

5 0

Answer:

7,12,17,22,27

Step-by-step explanation:

You just plug in 1,2,3,4,5 as n and add your values

so 7+5(1-1)=7

7+5(2-1)= 12 and so on

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(8 + 4 X 3) x 6 32 – 2 x3

kaheart [24]

Answer:

120 and 26

Step-by-step explanation:

( 8 + 4 * 3 ) * 6

Using BODMAS rule,

[ 8 + ( 4 * 3 ) ] * 6

= ( 8 + 12 ) * 6

= 20 *6

= 120

32 – 2 x 3

Using BODMAS rule,

32 - ( 2 * 3 )

= 32 - 6

= 26

Hope this answer was helpful!!

Regards..

4 0

3 years ago

Read 2 more answers

Cos(−θ)=√3/3, sinθ<0

Delicious77 [7]

Answer:

$\sin\theta=-\frac{\sqrt{6}}{3}$

Step-by-step explanation:

The given trigonometric equation is $\cos(-\theta)=\frac{\sqrt{3} }{3}$ .

We can either use the Pythagorean identity or the right angle triangle to solve for $\sin\theta$ .

According to the Pythagorean identity,

$\cos^2\theta+\sin^2\theta=1$

Recall that, the cosine function is an even function, therefore

$\cos(-\theta)=\cos(\theta)$

$\Rightarrow \cos(\theta)=\frac{\sqrt{3} }{3}$ .

We substitute this value in to the above Pythagorean identity to get;

$(\frac{\sqrt{3}}{3})^2+\sin^2\theta=1$

$\Rightarrow \frac{3}{9}+\sin^2\theta=1$

$\Rightarrow \sin^2\theta=1-\frac{3}{9}$

$\Rightarrow \sin^2\theta=\frac{6}{9}$

$\Rightarrow \sin\theta=\pm \sqrt{\frac{6}{9}}$

$\Rightarrow \sin\theta=\pm \frac{\sqrt{6}}{3}$

But we were given that,

$\sin\theta\:$ , so we choose the negative value.

$\Rightarrow \sin\theta=-\frac{\sqrt{6}}{3}$

The correct answer is B

7 0

4 years ago

What is the square root of 180x^9y^16 in simplest form?

Varvara68 [4.7K]

$\sqrt{180x ^{9y ^{16} } }$

Apply radical rule :

$\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$

$\sqrt{180} \sqrt{x ^{9y^{16} } }$

Break the number to its primes : $180 : 2^2*3^2*5$

$\sqrt{2^2*3^2*5}$

Apply radical rule :

 $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$

$\sqrt{5} \sqrt{2^2} \sqrt{3^2}$

Apply radical rule :

$\sqrt[n]{a^n} =a$

$\sqrt{2^2} =2$

$2* \sqrt{5} \sqrt{3^2}$

Apply radical rule :

 $\sqrt[n]{a^n} =a$

$\sqrt{3^2} =3$

$= 2*3* \sqrt{5}$

Refine:

$\sqrt{5} *6$

$\sqrt{5} *6 \sqrt{x ^{9y ^{16} } }$

Apply radical rule :

$\sqrt[n]{a^m} = a \frac{m}{n}$

$\sqrt{x ^{9y ^{16} } } = x \frac{9y ^{16} }{2}$

$= \sqrt{5} *6x \frac{9y ^{16} }{2}$

hope this helps!

6 0

4 years ago

PLEASE HELP ME ASAP !!! JUST ANSWER ONE OR BOTH PLEASE HELP!!

Sliva [168]

Use equation $A=P(1-r)^{t}$

Question 1: Need to find A:
$A=370,000(1-0.043)^{11} =228157.$

Question 2: Need to find t, use LOGARITHM:
$1-r=1-0.0106=0.9894 \\ log( \frac{A}{P})=tlog(0.9894)$
A=35000
P=49339
$\frac{A}{P}=0.7093779769 \\ \frac{log(0.7093...)}{log(0.9894} =t$
$32.221104307=t=32years.$
So 2010+32 = 2042.

8 0

3 years ago

Read 2 more answers

I need to know how to get the answer

Ganezh [65]

Answer:Bc there r more students that have an A it is more likely that a student earned an A on the math test :) hope that helped

5 0

3 years ago