Answer:
A = 3
B = -5
C = 2
Step-by-step explanation:
The way to format a quadratic equation is: 
, so the first step to solving this is to format it in the right way, where the 
comes first, the 
second, and the number alone.
After formatting, your equation should look like this: 
From here, you can see the the <em>a </em> is 3, the <em>b</em> is -5, and the <em>c </em>is 2
If the sum of an integer and 7 more than the next consecutive integer is 66 then the integers are 29 and 30.
Given that the sum of an integer and 7 more than the next consecutive integer is 66.
Integer is a number that is written without a fraction component. It can be positive as well as negative.
let the first integer be x.
Consecutive integer will be x+1.
Sum of integer and 7 more than the next consecutive integer is 66.
Sum according to the given information=x+x+1+7
=2x+8
2x+8=66
2x=66-8
2x=58
x=58/2
x=29
Next integer=29+1-30.
Hence if the sum of an integer and 7 more than the next consecutive integer is 66 then the integers are 29 and 30.
Learn more about integers at brainly.com/question/17695139
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30m/g
There isn't much to it. What are the options?
Solutions
To solve the problem the first step is to m<span>ultiply the whole number by the fraction's denominator (4 x 3).Add the numerator (2) to the product.
4 * 3 = 12
12 + 2 = 14
= 14/3 </span>
