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Juliette [100K]
3 years ago
13

3 A jet plane accelerated along a straight runway from rest to a

Physics
1 answer:
aleksklad [387]3 years ago
8 0

Explanation:

v=140 m/s

t=50s

u=0

change of velocity = v-u

140-0=140 m/s

for acceleration:

from Newton's first law of motion:

v=u+at

140=0+a50

50a=140

a=140/50

a=2.8 m/s²

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