Humans should be concerned with continental drift and plate tectonics because these forces have a major impact on the environment and also lead to major natural disasters. Shifts in tectonic plates lead to earthquakes which can also cause things like typhoons or tsunamis. Therefore, begin knowledgeable about the locations of fault lines and areas with the high potential for natural disasters as a result of shifting plates is very important.
Answer: option (D)
Explanation:
The potential energy of each of the students is given below as
P.E(student A) = mgh, where m = mass of student A, g is acceleration due to gravity and h = height of the high dive structure.
The mass of student B is twice as much as that of A, hence his mass is 2m and his potential energy is given below as
P.E ( student B) =2mgh = 2(mgh)
Recall that the relationship between potential energy and work done is that
Work done = - (change in potential)
For student A, work done = - mgh
For student B, work done = - 2mgh
From the equations above it can be seen that student B will do twice the work in getting to the high dive structure than student A hence validating option D.
Answer:
60 Ω
Explanation:
R(com) = 15 Ω
1/R(com) = 1/R1 + 1/R2 + 1/R3 ..... + 1/Rn
1/15 = 1/20 + 1/R2
1/R2 = 1/15 - 1/20
1/R2 = (4 - 3) / 60
1/R2 = 1/60
R2 = 60 Ω
así, la combinada de resistencia necesaria es 60 Ω
Answer:
A combined wave of extra height will produce every other wave.
Explanation:
One wave Crest can catch up to another wave Crest if the group of waves are from different places.
Here the two group of waves have different wavelength but travelling together in the same direction so when they combine,they will produce every other wave.
Answer:
Efriction = 768.23 [kJ]
Explanation:
In order to solve this problem we must use the principle of energy conservation. Where it tells us that the energy of a system plus the work applied or performed by that system, will be equal to the energy in the final state. We have two states the initial at the time of the balloon jump and the final state when the parachutist lands.
We must identify the types of energy in each state, in the initial state there is only potential energy, since the reference level is in the ground, at the reference point the potential energy is zero. At the time of landing the parachutist will only have potential energy, since it reaches the reference level.
The friction force acts in the opposite direction to the movement, therefore it will have a negative sign.
where:
m = mass = 56 [kg]
h = elevation = 1400 [m]
v = velocity = 5.6 [m/s]
![(56*9.81*1400)-E_{friction}=\frac{1}{2}*56*(5.6)^{2}\\769104 -E_{friction}= 878.08 \\E_{friction}=769104-878.08\\E_{friction}=768226[J] = 768.23 [kJ]](https://tex.z-dn.net/?f=%2856%2A9.81%2A1400%29-E_%7Bfriction%7D%3D%5Cfrac%7B1%7D%7B2%7D%2A56%2A%285.6%29%5E%7B2%7D%5C%5C769104%20-E_%7Bfriction%7D%3D%20878.08%20%5C%5CE_%7Bfriction%7D%3D769104-878.08%5C%5CE_%7Bfriction%7D%3D768226%5BJ%5D%20%3D%20768.23%20%5BkJ%5D)
