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Anuta_ua [19.1K]
3 years ago
15

A football player kicks a ball with a mass of 0.5 kg. The average acceleration of the football was 15 m/s/s. How much force did

the kicker apply to the football?
Physics
1 answer:
Nikolay [14]3 years ago
8 0

Answer:

i think its 8.2

Explanation:

You might be interested in
Practice
marshall27 [118]

Answer:

In both cases the height is greater than 10.3 m

Explanation:

Pressure is defined by the relationship

       P = F / A

in this case the force is the weight of the two gases

       F = W = m g

If we use the definition of density

      ρ = m / V

      V = A h

      m = ρ A h

we substitute

       P = ρ g h

       h = \frac{P}{\rho g}

For this case the density of the gases is

       ρ' = 0.9 \rho_{water}

       h =\frac{P}{0.9 \ \rho_{water} g}

we calculate

     ρ’= 0.9 \rho_{water}

     h = 1 105 / (0.9 1000 9.8)

     h = 11.3 m

      ρ’= 0.8 \rho_{water}

       h = 1 105 / (0.8 1000 9.8

       h = 12.8 m

In both cases the height is greater than 10.3 m

4 0
3 years ago
A mouse is running across a room with a speed of 2.2 m/s. The mass of the mouse is 1.4 kg. What is the Kinetic Energy of the mou
valina [46]

Answer:

<h2>3.39 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 1.4 \times  {2.2}^{2}  \\  = 0.7 \times 4.84 \\  = 3.388 \:  \:  \:  \:  \:  \:  \:  \:  \:

We have the final answer as

<h3>3.39 J</h3>

Hope this helps you

6 0
3 years ago
Read 2 more answers
A jet, sitting on the runway, takes off and accelerates at 8.0 m/s for 16s. How far did the jet travel down the runway?
nydimaria [60]

Answer:

2.4 m/s". 1

Explanation:

A jet with mass m = 8 x 10* kg jet accelerates down the runway for takeoff at 2.4 m/s". 1

8 0
3 years ago
A 10.0 cm3 sample of copper has a mass of 89.6
Romashka-Z-Leto [24]
Density is mass divides by volume, so
89.6g / 10cm^3 =8.96g /cm^3

*cm^3 is a standard unit of volume*
4 0
4 years ago
When a vertical beam of light passes through a transparent medium, the rate at which its intensity I decreases is proportional t
antoniya [11.8K]

Answer:

Intensity of beam 18 feet below the surface is about 0.02%

Explanation:

Using Lambert's law

Let dI / dt = kI, where k is a proportionality constant, I is intensity of incident light and t is thickness of the medium

then dI / I = kdt

taking log,

ln(I) = kt + ln C

I = Ce^kt

t=0=>I=I(0)=>C=I(0)

I = I(0)e^kt

t=3 & I=0.25I(0)=>0.25=e^3k

k = ln(0.25)/3

k = -1.386/3

k = -0.4621

I = I(0)e^(-0.4621t)

I(18) = I(0)e^(-0.4621*18)

I(18) = 0.00024413I(0)

Intensity of beam 18 feet below the surface is about 0.2%

3 0
3 years ago
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