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3 years ago

Which of the following is not considered a major work flow structure?

Physics

1 answer:

mixas84 [53]3 years ago

8 0

Answer:

The correct option is;

D. Fabrication

Explanation:

A workflow flow is a detailed business process consisting of a series of required interconnected tasks in directed graph format that is executable by workflow management system.

Considering each of the options, we have

A. Work center

This consists of part of the transformation input to output. The location

B. Project

This is the unique identifier of the task to be processed

C. Assembly line

Forms part of the required input where transformation takes place and items are being processed within the assembly line

D. Fabrication

Here the item is fixed, without motion, therefore this is not considered a major work flow structure

E. Continuous flow

Here again, the items are being processed and are in motion, which constitutes a workflow structure.

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Why does a balloon fully inflated with air rise up vertically for some distance whenpunctured from below?

Virty [35]

Newton's second and third law can be found the correct answer is:

The force of the air leaving the balloon by action and reaction causes it to have a positive acceleration upward and rise.

Pressure is defined by the relationship between forces and area,

P = F / A

Where P is pressure, F is force and A is area

F = P A

Newton's second law is that the sum of the external forces of a body is proportional to the mass of the body and the acceleration

Newton's third law or action and reaction says that forces in nature appear in pairs on the two interacting bodies, the magnitude of the force is equal, but in the opposite direction; each one is applied to one of the bodies.

A free-body diagram of the process is shown in the attachment

B + F - W = m a

W = m g

Where B is the thrust, F the force of air exit, W the weight, m the mass and the acceleration of the body

Archimedes' principle states that the vertical thrust on a body is equal to the fart of the dislodged fluid, in this case air.

B =ρ_{air} g V_{air}

Where ρ and V_ {air} are the density and volume of the air, respectively,

It's substitute

ρ_{air} g V_{air} + P A - m g = m a

a =

The mass of the body is formed by the mass of the balloon plus the mass of air that it contains

Let's analyze this expression in three moments

Before opening the hole at the bottom. The second term is zero, so the thrust is not enough to lift the balloon, the acceleration is negative.

Just after opening. The force of the air coming out that by the law of action and reaction creates a force of equal magnitude and upward direction on the balloon. The sum of these two forces makes the acceleration positive, therefore the balloon rises

After the pressure inside the balloon is equal to the atmospheric pressure. Tthis case the second term is zero again and the balloon begins to descend with an acceleration less than the acceleration of gravity.

In conclusion with Newton's second and third law we find the correct answer is:

The force of the air leaving the balloon by action and reaction law causes it to have a positive acceleration upward and rise.

Learn more about Newton's law here:

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3 years ago

The data on the human genome database can be used to determine what

oee [108]

The Genome Database (GDB, http://www.gdb.org ) is a public repository of data on human genes, clones, STSs, polymorphisms and maps

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3 years ago

Imagine that the satellite described in the problem introduction is used to transmit television signals. You have a satellite TV

Korolek [52]

Complete Question

A satellite in geostationary orbit is used to transmit data via electromagnetic radiation. The satellite is at a height of 35,000 km above the surface of the earth, and we assume it has an isotropic power output of 1 kW (although, in practice, satellite antennas transmit signals that are less powerful but more directional).

Imagine that the satellite described in the problem introduction is used to transmit television signals. You have a satellite TV reciever consisting of a circular dish of radius R which focuses the electromagnetic energy incident from the satellite onto a receiver which has a surface area of 5 cm2.

How large does the radius R of the dish have to be to achieve an electric field vector amplitude of 0.1 mV/m at the receiver?

For simplicity, assume that your house is located directly beneath the satellite (i.e. the situation you calculated in the first part), that the dish reflects all of the incident signal onto the receiver, and that there are no losses associated with the reception process. The dish has a curvature, but the radius R refers to the projection of the dish into the plane perpendicular to the direction of the incoming signal.

Give your answer in centimeters, to two significant figures.

Answer:

The radius of the dish is $R = 18cm$

Explanation:

From the question we are told that

The radius of the orbit is = $R = 35,000km = 35,000 *10^3 m$

The power output of the power is $P = 1 kW = 1000W$

The electric vector amplitude is given as $E = 0.1 mV/m = 0.1 *10^{-3}V/m$

The area of thereciever is $A_R = 5cm^2$

Generally the intensity of the dish is mathematically represented as

$I = \frac{P}{A}$

Where A is the area orbit which is a sphere so this is obtained as

$A = 4 \pi r^2$

$= (4 * 3.142 * (35,000 *10^3)^2)$

$=1.5395*10^{16} m^2$

Then substituting into the equation for intensity

$I_s = \frac{1000}{1.5395*10^{16}}$

$= 6.5*10^ {-14}W/m2$

Now the intensity received by the dish can be mathematically evaluated as

$I_d = \frac{1}{2} * c \epsilon_o E_D ^2$

Where c is thesped of light with a constant value $c = 3.0*10^8 m/s$

$\epsilon_o$ is the permitivity of free space with a value $8.85*10^{-12} N/m$

$E_D$ is the electric filed on the dish

So since we are to assume to loss then the intensity of the satellite is equal to the intensity incident on the receiver dish

Now making the eletric field intensity the subject of the formula

$E_D = \sqrt{\frac{2 * I_d}{c * \epsilon_o} }$

substituting values

$E_D = \sqrt{\frac{2 * 6.5*10^{-14}}{3.0*10^{8} * 8.85*10^{-12}} }$

$= 7*10^{-6} V/m$

The incident power on the dish is what is been reflected to the receiver

$P_D = P_R$

Where $P_D$ is the power incident on the dish which is mathematically represented as

$P_D = I_d A_d$

$= \frac{1}{2} c \epsilon_o E_D^2 (\pi R^2)$

And $P_R$ is the power incident on the dish which is mathematically represented as

$P_R = I_R A_R$

$= \frac{1}{2} c \epsilon_o E_R^2 A_R$

Now equating the two

$\frac{1}{2} c \epsilon_o E_D^2 (\pi R^2) = \frac{1}{2} c \epsilon_o E_R^2 A_R$

Making R the subject we have

$R = \sqrt{\frac{E_R^2 A_R}{\pi E_D^2} }$

Substituting values

$R = \sqrt{\frac{(0.1 *10^{-3})^2 * 5}{\pi (7*10^{-6})^ 2} }$

$R = 18cm$

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3 years ago

Here's a quick story if a boy walks to the woods at night and slender man comes along what is most likely to happen put your ans

ANEK [815]

Answer:

the boy would go missing

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The weld current between pulses is know as ______

Brut [27]

Answer:

the pulse arc system

Explanation:

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