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Vesna [10]
4 years ago
9

25 points plz help!!! Calculate the equation of the line through the points (-1, 1), (4, 0), and (24, -4)

Mathematics
1 answer:
Mila [183]4 years ago
6 0
So if the line is linear we can use slope intercept form to find the equation of the points: y=mx+b

To calculate m, the slope we subtract two of the points (I’ll use the first two):

(-1, 1)
(4, 0)

This equals 0-1/4+1, which simplifies to -1/5

So the slope is -1/5 and we can put that into slope intercept form along with a point to get b, the y-intercept.

So, y=-1/5x+b

Now we substitute x and y with a point.

1=-1/5(-1)+b
1=1/5+b
b=4/5

So the equation is:
y=-1/5x+4/5

I hope this helps!
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Answer:

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Find the point at which the line with parametric equations x = 2 3t, y =-4t, z =5 t intersects the plane 4x 5y -2z=18
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It looks like you have

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\begin{cases}x=2+3(-2)\\y=-4(-2)\\z=5+(-2)\end{cases} \implies (x,y,z) = \boxed{(-4,8,3)}

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