9.
They are: 59, 61, 67, 71, 73, 79, 83, 89 & 97.
B. No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32
Perimeter = 2(l + w)
Perimeter = 64
Assuming: P = 64; w = 11 ; l = ?
64 = 2(l + 11)
64/2 = l + 11
32 - 11 = l
length = 21.
Answer:
the 3rd A
Step-by-step explanation:
ABACB = 5 altogether
ABACB ABA = 8
The answer to this is negative
Answer:
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Step-by-step explanation:
