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Colt1911 [192]
3 years ago
7

Kelso is in charge of a bake sale. On each table, t, there will be a platter of 24 cookies and 2 bowls of brownies with b browni

es inside. Kelso needs an additional 150 cookies to replace what he sells. This situation can be written as the following expression: 24t + (2b)t + 150 How many total sweets are there if there are 7 tables and 12 brownies in each bowl? 168 336 486 512
Mathematics
1 answer:
Phantasy [73]3 years ago
8 0
24*7 = 168
(2*12)*7=168
168*2=336

336 Total sweets

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Problem page the sum of two numbers is 56 . the smaller number is 16 less than the larger number. what are the numbers?
igomit [66]
Create equations using the given information
1) x+y=56
2) y=x-16
Substitute the value of y into the 1st equation and simplify
1)x+x-16=56
   2x=72
   x=36
Substitute the value of x into the 1st equation and simplify
1)x+y=56
   36+y=56
   y=20

Answer: 20 and 36

8 0
3 years ago
Please help if you can! :)
mina [271]

9514 1404 393

Answer:

  A. no solution

  B. unique solution: (x, y) = (0, 0)

Step-by-step explanation:

For these problems, you can subtract the second equation from the first to get something of the form ...

  0 = (expression)

The solution of that will tell you the answer.

__

A. (2x +3y) -(2x +3y) = (4) -(9)

  0 = -5 . . . . . . . . no values of x or y will make this true: NO SOLUTION

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B. (y) -(y) = (6x) -(x)

  0 = 5x

  0 = x . . . . . . divide by the coefficient of x.

  y = x = 0

The unique solution is (x, y) = (0, 0).

5 0
3 years ago
Plz A total of 41 and 1/3 tons of gravel was split between four dump trucks. How many tons of gravel did each truck hold?
12345 [234]
10 1/3.
EXPLANATION
41 1/3 tons divided by 4 trucks = 10 1/3 tons per truck.
HOPE THIS HELPED HAVE A GUD DAY!
5 0
3 years ago
How do i factor this trinomial 5y^2 — 7y — 6 ​
scZoUnD [109]

Answer:

(5y+3) x (y-2)

Step-by-step explanation:

5y^2-7y-6

5y^2+3y-10y-6

y(5y+3(-2(5y+3)

(5y+3) x (y-2)

5 0
3 years ago
A quality control specialist at a pencil manufacturer pulls a random sample of 45 pencils from the assembly line. The pencils ha
amm1812

Answer:

The P-value you would use to test the claim that the population mean of  pencils produced in that factory have a mean length equal to 18.0 cm is 0.00736.

Step-by-step explanation:

We are given that a quality control specialist at a pencil manufacturer pulls a random sample of 45 pencils from the assembly line.

The pencils have a mean length of  17.9 cm. Given that the population standard deviation is 0.25 cm.

Let \mu = <u><em>population mean length of  pencils produced in that factory.</em></u>

So, Null Hypothesis, H_0 : \mu = 18.0 cm     {means that the population mean of  pencils produced in that factory have a mean length equal to 18.0 cm}

Alternate Hypothesis, H_A : \mu\neq 18.0 cm     {means that the population mean of  pencils produced in that factory have a mean length different from 18.0 cm}

The test statistics that will be used here is <u>One-sample z-test</u> statistics because we know about the population standard deviation;

                           T.S.  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean length of pencils = 17.9 cm

           \sigma = population standard deviation = 0.25 cm

           n = sample of pencils = 45

So, <u><em>the test statistics</em></u> =  \frac{17.9-18.0}{\frac{0.25}{\sqrt{45} } }  

                                    =  -2.68

The value of z-test statistics is -2.68.

<u>Now, the P-value of the test statistics is given by;</u>

         P-value = P(Z < -2.68) = 1 - P(Z \leq 2.68)

                      = 1- 0.99632 = 0.00368

For the two-tailed test, the P-value is calculated as = 2 \times 0.00368 = 0.00736.

7 0
3 years ago
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