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balandron [24]
3 years ago
8

In the image below, which objects would have a greater gravitational force between them, Objects A and B, or Objects B and C? Gi

ve one supporting detail for your answer.
Physics
1 answer:
Arada [10]3 years ago
4 0
I don't see an image, but the force of gravity depends on mass and distance. If the mass and the distance are different, you divide (mass÷distance).the greater the number the greater the force of gravity.

Tell me if you need more info.
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If 5kg Stone and 1kg stone throw the from the building which will land more fa ster and why?​
sweet [91]

Answer:

Both stones will land at the same time because both stones will fall with the same acceleration through the same height.

Explanation:

We are given that

Mass of stone ,m1=5 Kg

Mass of stone, m2=1 kg

We have to find which stone more faster will land and why.

h=u+\frac{1}{2}gt^2

Initial velocity of both stones=0

h=\frac{1}{2}gt^2

t^2=\frac{h}{g}

t=\sqrt{\frac{h}{g}}

t_1=t_2=\sqrt{\frac{h}{g}}

Because both stones are thrown from the same height.

Both stones will land at the same time because both stones will fall with the same acceleration through the same height  and the acceleration  does not depend of its mass.

5 0
3 years ago
A wave travels at a speed of 242 m/s. If the distance between crests is 0.11
Lesechka [4]

The correct answer is D. 2200 Hz

Explanation:

The frequency of a wave is measured in hertz (Hz) and refers to how often a wave passes through a point during a specific time. This factor can be calculated if you divide the velocity of the wave by the wavelength (distance between crests) this means f (frequency) = v (velocity) / λ (wavelength).

f (frequency) =  242 m/s (velocity) / 0.11 (wavelegth)

f = 2200 Hz

According to this, the frequency of the wave, in this case, is 2200 Hz

5 0
3 years ago
2. A common physics experiment involves lowering an open tube into a cylinder of water and moving the tube up and down to adjust
notsponge [240]

Answer:

Explanation:

This question pertains to resonance in air column.  It is the case of closed air column in which fundamental note is formed at a length which is as follows

l = λ / 4 where l is length of tube and λ is wave length.

here l = .26 m

λ = .26 x 4 = 1.04 m

frequency of sound = 330 Hz

velocity of sound = frequency x wave length

= 330 x 1.04

= 343.2 m /s

b )

Next overtone will be produced at 3 times the length

so next length of air column = 3 x 26

= 78 cm

c )

If frequency of sound = 256 Hz

wavelength = velocity / frequency

= 343.2 / 256

= 1.34 m

= 134 cm

length of air column for resonance

= wavelength / 4

134/4

= 33.5 cm

7 0
3 years ago
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