Answer:
Given,
mass of man = 100 N = 10 kg
height = h = 25m
since the man does not move anything with his force, work done by him is zero
work done on the man = gain in potential energy
P.E=mgh
P.E=10×9.8×25
P.E=2.45KJ
Explanation:
so, potential energy gained by man is 2.45 KJ
Then the maximum height of the catapult will be 69.78 meters.
<h3>What is kinematics?</h3>
The study of motion without considering the mass and the cause of the motion. The equation of motion is given below.
v = u + at
s = ut + (1/2)at²
v² = u² + 2as
A catapult can project a projectile at a speed as high as 37.0 m/s. (a) if air resistance can be ignored.
a = - 9.81 m/s²
u = 37 m/s
v = 0
s = h
Then the maximum height of the catapult will be given by the third equation.
v² = u² + 2as
0² = 37² - 2 × 9.81 × h
h = 37² / (2 × 9.81)
h = 69.78 meters
Then the maximum height of the catapult will be 69.78 meters.
More about the kinematics link is given below.
brainly.com/question/7590442
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Hey there!
<span>because it slows down, which causes it to bend is the reason why light refracts when it encounters the glass in the lens
Hope this helps!</span>
To resolve these forces we have to make use of the sines and cosines.
To resolve this force in 30 degree north of west, the answer will be
100*sin(30)
The answer will be 50N
Now to resolve the force acting 60 degree north of east
100* cos(60)
The answer will be 50N.
This also adds to the total force acting that is 50+50=100N. This is the way forces are resolved according to their specified angles.
Answer:
To increase kinetic friction, the amount of fine water droplets sprayed before the game is limited.
To reduce kinetic friction. increase the amount of fine water droplets during pregame preparation and sweeping in front of the curling stones.
Explanation:
In curling sports, since the ice sheets are flat, the friction on the stone would be too high and the large smooth stone would not travel half as far. Thus controlling the amount of fine water droplets sprayed before the game is limited pregame is necessary to increase friction.
On the other hand, reducing ice kinetic friction involves two ways. The first way is adding bumps to the ice which is known as pebbling. Fine water droplets are sprayed onto the flat ice surface. These droplets freeze into small "pebbles", which the curling stones "ride" on as they slide down the ice. This increases contact pressure which lowers the friction of the stone with the ice. As a result, the stones travel farther, and curl less.
The second way to reduce the kinetic friction is sweeping in front of the large smooth stone. The sweeping action quickly heats and melts the pebbles on the ice leaving a film of water. This film reduces the friction between the stone and ice.
