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3 years ago

How long would it take for a sound impulse to travel through an aluminum rod 1,500 meters long?

Physics

2 answers:

Yuliya22 [10]3 years ago

6 0

The answer is:

0.29

............................................

NNADVOKAT [17]3 years ago

5 0

I believe the answer is 0.29.

You might be interested in

Coulomb's law is expressed mathematically as

nataly862011 [7]

Force between two charges =

( 1/4πε₀ ) · (Charge #1) · (Charge #2) / (Distance between them)²

in the direction away from each other.

In other words, if the force is positive, the charges are repelling.
If the force is negative, the charges are attracting.

4 0

3 years ago

a physics student throws a stone horizontally off a cliff. one second later, he throws a second identical stone in exactly the s

Virty [35]

The second stone hits the ground exactly one second after the first.

The distance traveled by each stone down the cliff is calculated using second kinematic equation;

$h = v_0_yt + \frac{1}{2} gt^2$

where;

t is the time of motion
$v_0_y$ is the initial vertical velocity of the stone = 0

$h = \frac{1}{2} gt^2$

The time taken by the first stone to hit the ground is calculated as;

$t_1 = \sqrt{\frac{2h}{g} }$

When compared to the first stone, the time taken by the second stone to hit the ground after 1 second it was released is calculated as

$t_2 = \sqrt{\frac{2h}{g} } + 1$

$t_2 = t_1 + 1$

Thus, we can conclude that the second stone hits the ground exactly one second after the first.

"Your question is not complete, it seems be missing the following information;"

A. The second stone hits the ground exactly one second after the first.

B. The second stone hits the ground less than one second after the first

C. The second stone hits the ground more than one second after the first.

D. The second stone hits the ground at the same time as the first.

Learn more here:brainly.com/question/16793944

8 0

3 years ago

What causes the movement of the crust that leads to volcanoes, mountains, and seafloor spreading?

Salsk061 [2.6K]

Answer:

B.convection currents in the mantle

Explanation:

4 0

2 years ago

The whole body metabolic rate of a bottlenose dolphin is 8000kcalsday. The dolphin weighs 190kg. What is the mass specific metab

Komok [63]

Answer: 42.1

Explanation:

Mass specific metabolic rate of a dolphin can be defined as the rate at which the dolphin consume energy per unit mass of body weight.

R = E/M

Where R = mass specific metabolic rate

E = Energy consumption = 8000kcalsday

M = mass = 190kg

R = 8000kcalsday/190kg

R = 42.1

4 0

3 years ago

A 20 KeV electron emits two bremsstrahlung photons as it is being brought to rest in two successive decelerations. The wavelengt

Degger [83]

Answer:

λ₁ = 87.5 10⁻¹² m , λ₂ = 2.175 10⁻¹⁰ m, E₂ = 5.8 10³ eV

Explanation:

In this case you can use the law of conservation of energy, all the energy of the electron is converted into energized emitted photons

Let's reduce to the SI system

E₀ = 20 10³ eV (1.6 10⁻¹⁹ J / 1eV) = 3.2 10⁻¹⁵ J

Δλ = 1.30 A = 0.13 nm = 0.13 10⁻⁹ m

Ef = E₁ + E₂

E₀ = Ef

E₀ = E₁ + E₂

The energy can be found with the Planck equation

E = h f

c = λ f

f = c / λ

E = hc / λ

They indicate that the wavelength of the second photon is

λ₂ = λ₁ +0.130 10⁻⁹

We replace

E₀ = hv / λ₁ + hc / ( λ₁ + 0.130 10⁺⁹)

E₀ / hv = 1 / λ₁ + 1 / ( λ₁ + 0.13 10⁻⁹)

3.2 10⁻¹⁵ / (6.63 10⁻³⁴ 3 10⁸) = ( λ₁ + 0.13 10⁻⁹ + λ₁) / λ₁ ( λ₁ + 0.13 10⁻⁹)

1.6 10¹⁰ ( λ₁² +0.13 10⁻⁹ λ₁) = 2 λ₁ + 0.13 10⁻⁹

λ₁² + 0.13 10⁻⁹ λ₁ = 1.25 10⁻¹⁰ λ₁ + 8.125 10⁻²¹

λ₁² + 0.005 10⁻⁹ λ₁ = 8.125 10⁻²¹

λ₁² + 5 10⁻¹² λ₁ - 8.125 10⁻²¹ = 0

Let's solve the second degree equation

λ₁ = [-5 10⁻¹² ±√((5 10⁻¹²)² + 4 8.125 10⁻²¹)] / 2

λ₁ = [-5 10⁻¹² ±√(25 10⁻²⁴ +32.5 10⁻²¹)] / 2 = [-5 10⁻¹² ±√ (32525 10⁻²⁴)] / 2

λ₁ = [-5 10⁻¹² ± 180 10⁻¹²] / 2

λ₁ = 87.5 10⁻¹² m

λ₂ = -92.5 10⁻¹² m

We take the positive wavelength

The wavelength of the photons is

λ₁ = 87.5 10⁻¹² m

λ₂ = λ₁ + 0.13 10⁻⁹

λ₂ = 87.5 10⁻¹² + 0.13 10⁻⁹

λ₂ = 0.2175 10⁻⁹ m = 2.175 10⁻¹⁰ m

The energy after the first deceleration is

E₂ = E₀ –E₁

E₂ = E₀ –hc / λ₁

E₂ = 3.2 10⁻¹⁵ - 6.63 10⁺³⁴ 3 10⁸ / 87.5 10⁻¹²

E₂ = 3.2 10⁻¹⁵ - 2.27 10⁻¹⁵

E₂ = 0.93 10⁻¹⁵ J

E₂ = 0.93 10⁻¹⁵ J (1 eV / 1.6 10⁻¹⁹ J)

E₂ = 5.8 10³ eV

7 0

3 years ago