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kolbaska11 [484]
3 years ago
11

How long would it take for a sound impulse to travel through an aluminum rod 1,500 meters long?

Physics
2 answers:
Yuliya22 [10]3 years ago
6 0

The answer is:

0.29

............................................

NNADVOKAT [17]3 years ago
5 0
<span>I believe the answer is 0.29.</span>
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A person travels by car from one city to another. She drives for 23.5 min at 74.5 km/h, 15.9 min at 111 km/h, 49.2 min at 38.7 k
Drupady [299]
The product of speed and time is distance. To calculate the total distance you multiple the speed in kilometers per second by the time at that speed in seconds, do this for all 3 different speeds then add them up, the 17.4 minutes eating does not affect the answer at all. to convert from minutes to seconds multiply time in minutes by 60, to convert from km/h to km/s divide km/h by 3600.

(23.5x60)x(74.5/3600) = 29.2km (rounded to 1 decimal place)
+
(15.9x60)x(111/3600) = 29.4km (rounded to 1 decimal place)
+
(49.2x60)x(38.7/3600) = 31.7km
=90.3km

The brackets are not necessary but i think it makes it more clear what is happening in your working.

3 0
2 years ago
Do you think that rubbing two pieces of woods together would have more or less friction than wood rubbing against smooth metal ?
salantis [7]

Answer: More friction

Explanation: The wood would probably splinter, causing even more friction, while the metal would probably smooth the wood out.

7 0
3 years ago
A tank contains gas at 13.0°C pressurized to 10.0 atm. The temperature of the gas is increased to 95.0°C, and half the gas is re
fomenos

Answer:

The pressure of the remaining gas in the tank is 6.4 atm.

Explanation:

Given that,

Temperature T = 13+273=286 K

Pressure = 10.0 atm

We need to calculate the pressure of the remaining gas

Using equation of ideal gas

PV=nRT

For a gas

P_{1}V_{1}=nRT_{1}

Where, P = pressure

V = volume

T = temperature

Put the value in the equation

10\times V=nR\times286....(I)

When the temperature of the gas is increased

Then,

P_{2}V_{2}=\dfrac{n}{2}RT_{2}....(II)

Divided equation (I) by equation (II)

\dfrac{P_{1}V}{P_{2}V}=\dfrac{nRT_{1}}{\dfrac{n}{2}RT_{2}}

\dfrac{10\times V}{P_{2}V}=\dfrac{nR\times286}{\dfrac{n}{2}R368}

P_{2}=\dfrac{10\times368}{2\times286}

P_{2}= 6.433\ atm

P_{2}=6.4\ atm

Hence, The pressure of the remaining gas in the tank is 6.4 atm.

4 0
2 years ago
Janet was pulling a box that weighed 20N across 5m. How much work did she exert?
Galina-37 [17]

Answer:

100nm

Explanation:

Work=Force×distance

=20×5

=100nm

6 0
2 years ago
PLEASE HELP WITH THIS QUESTION. ​
Sophie [7]

Answer:

#2 and #3 respectively

Explanation:

6 0
3 years ago
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