How do you do this problem?
1 answer:
There are not too many things that are more insoluble than AgCl. When you actually do this experiment, virtually all of the AgCl sinks to the bottom of the test tube (or whatever container you are doing it in). The CuCl2 is very soluble. It is a gorgeous Forest Green with a very slightly blue tinge so you can tell that you are successful.
CuCl2 is very soluble.
That makes A incorrect.
AgCl is really insoluble
Looks like B is the answer.
C is just wrong. No complex is formed. The equation is a double replacement.
AgNO3 + HCl ====> AgCl(s) + HNO3 Not a good example but it is correct.
Cu(NO3)2 + 2HCl ===> CuCl2 + 2HNO3
D is not true. Ag will react with the HCl That's how you get AgCl going to the bottom.
E A double replacement need not transfer electrons. In this case it does not. E is incorrect.
You might be interested in
A 1. 00 ml sample of an unknown gas effuses in 11. 1 min. an equal volume of h2 in the same apparatus under the same conditions effuses in 2. 42 minutes then the molar mass of the unknown gas is 41.9.
Molar mass of H2 = 2
Molar mass of unknown gas = ?
rate 1 = 11.1
rate 2 = 2.42
<h3>What is graham law? </h3>Graham's law states that the rate of diffusion or effusion of a given gas is inversely proportional to the square root of its molar mass.
By apply graham law
Rate1/rate2 = sqrt(MW2/MW1)
Thus, we found that the molar mass of the unknown gas is 41.9.
Learn more about graham's law: brainly.com/question/12415336
#SPJ4