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<h2>Question:- </h2>
A solution has a pH of 5.4, the determination of [H+].
<h2>Given :- </h2>- pH:- 5.4
- pH = - log[H+]
Take negative to other side
-pH = log H+
multiple Antilog on both side
(Antilog and log cancel each other )
Antilog (-pH) = [ H+ ]
New Formula :- Antilog (-pH) = [+H]
Now put the values of pH in new formula
Antilog (-5.4) = [+H]
we can write -5.4 as (-6+0.6) just to solve Antilog
Antilog ( -6+0.6 ) = [+H]
Antilog (-6) × Antilog (0.6) = [+H]
put the value in equation
Answer:
Approximately 1.9 kilograms of this rock.
Explanation:
Relative atomic mass data from a modern periodic table:
- Pb: 207.2;
- S: 32.06.
To answer this question, start by finding the mass of Pb in each kilogram of this rock.
89% of the rock is . There will be 890 grams of
in one kilogram of this rock.
Formula mass of :
.
How many moles of formula units in that 890 grams of
?
.
There's one mole of in each mole of
. There are thus
of
in one kilogram of this rock.
What will be the mass of that of
?
.
In other words, the in 1 kilogram of this rock contains
of lead
.
How many kilograms of the rock will contain enough to provide 1.5 kilogram of
?
.