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Snowcat [4.5K]
2 years ago
7

The mass of ethylene glycol (molar mass 62.1 g / mol), the main component of the antifreeze, must be added to 10.0 L of water to

obtain a solidified solution at -23 ° C. Assume a water density of 1 g / mL.
Chemistry
1 answer:
ser-zykov [4K]2 years ago
7 0
<h2> refer the attachment</h2>

<h2>If it is correct so mark as brainlest answer!</h2>

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Hi everyone can anyone help with this, the question and diagram is in the pic thx!
seraphim [82]

Answer:

QP

Explanation:

P has 9 electrons.

Electronic Configuration : 2, 7

Valence electrons : 7

P needs 1 electron to get stable electronic configuration.

Q has 3 electrons.

Electronic Configuration : 2, 1

Valence electrons : 1

P needs to loose 1 electron to get stable electronic configuration.

Q donates 1 electron,

Q -----> Q+ + 1 e-

P gains 1 electron,

P + 1 e- -----> P-

Q+ + P- -----> QP

This is an ionic compound.

8 0
3 years ago
If you have a 12.0 gram steel ball at sea level and then take it up to mt. Fuji what will change?
andrey2020 [161]
The air pressure. the air pressure increases as the altitude an object is at increases.
8 0
3 years ago
a square boat made from iron has overall dimensions of 2.00 cm x 11.0 cm x 11.0 cm. it has a mass of 213 g. water has a density
Stolb23 [73]
Density of boat  =  \frac{MASS}{VOLUME}
                           
                          =  \frac{213 g}{(2 cm  *  11 cm  *  11cm)}
 
                          =   0.88 g / cm³

Since the density of water is greater than the density of the boat ( 1 > 0.88) then that means, the boat will NOT sink.

B.

4 0
3 years ago
Read 2 more answers
Which factor affects a solute's solubility rather than its rate of solution?
Illusion [34]

Answer: A

Explanation:

I took the test it was A

4 0
3 years ago
A pound of margarine costs $1.39. What is the cost of a kilogram of margarine
den301095 [7]

Answer:

              3.064 $

Solution:

First of all we will find the number of pounds contained by one Kg. Therefore, it is found that,

                                    1 Kilogram  = 2.20462 Pounds

Hence, as given,

                        1 Pound of Margarine costs  =  1.39 Dollars

So,

                  2.20462 Pounds Margarine will cost  =  X Dollars

Solving for X,

                     X  =  (2.20462 Pounds × 1.39 Dollars) ÷ 1 Pound

                     X =  3.064 Dollars

8 0
3 years ago
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